Given :
- In a neutral atom that has an atomic mass of 22 and atomic number of 12.
To Find :-
Solution :-
<u>As </u><u>we</u><u> know</u><u> that</u><u>,</u>
- n(neutrons) + n(protons) = A
- n(neutrons) + 12 = 2 2
- n(neutrons) = 22-12
- n(neutrons) = 10
<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> </u><u>is </u><u>1</u><u>0</u><u>.</u>
Answer:
YES HE CAN
Step-by-step explanation:
Answer:
6 times
Step-by-step explanation:
Given
---- i.e. multiplies by -2
--- i.e. multiplies by 2
--- signals
Required
Number of times they have the same number
First, we list out all results of Ivan calculations.
To calculate Ivan's list, we simply multiply the current term by -2.
The 10 signals together with the first term, means there will be 11 terms in total
So, we have:
Next, list Adeline's
Compare the elements of the two lists, we have:
<em>Hence, they have the same number 6 times.</em>