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3 years ago

What is the value of f(-4)

Mathematics

1 answer:

maria [59]3 years ago

8 0

(-4) is the same as x, so looking the conditions that are the results for the function, you realize:

-2 is the result of the function to the values of X that are under -3: the result will be -2 if x < -3

x < -3 ; x = -4 ; -4 < -3 (it's true), in other words, -4 is less than -3, so f(-4) = -2

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4. Two families went camping. The Becker family was 4 miles west of the campsite lake. The Dunn family

tresset_1 [31]

They were 1 mile away from each other.

4-3=1 mile

8 0

3 years ago

The fit line equation is Y = -2.61x +152.51, where x is variable 1 and Y is variable 2. According to the equation, what is the e

egoroff_w [7]

The expected value of y when x is equals to 45 in the equation is 35.06

<h3>How to find variable from an equation?</h3>

The equation is given as follows;

y = -2.61x + 152.51

where

x = variable 1
y = variable 2

Therefore,

when

x = 45

y = -2.61x + 152.51

y = -2.61(45) + 152.51

y = - 117.45 + 152.51

y = 35.06

learn more on equation here: brainly.com/question/14279419

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5 0

1 year ago

Which set of numbers could represent the lengths of the sides of a right triangle? 16, 32, 36 5, 12, 13 6, 7, 8 8, 12, 16

Elden [556K]

5,12,13

5X5=25

12X12=144

25+144=169

answer: square root 169=13

6 0

3 years ago

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brilliants [131]

skjdnisujwndijbd

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4 0

2 years ago

Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1, given that f(0)=60

RSB [31]

Answer:

$f(x)=2x^{3}+24x^{2}+82x+60$

Step-by-step explanation:

we know that

The roots of the polynomial are the values of x when the value of the polynomial f(x) is equal to zero

The roots of the polynomial function are

x=-6 -----> (x+6)=0

x=-5 -----> (x+5)=0

x=-1 -----> (x+1)=0

The equation of the cubic polynomial is

$f(x)=a(x+6)(x+5)(x+1)$

where

a is the leading coefficient

Remember that

f(0)=60

That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

$60=a(0+6)(0+5)(0+1)$

$60=a(6)(5)(1)$

$60=30a$

$a=2$

$f(x)=2(x+6)(x+5)(x+1)$

Applying the distributive property

Convert to expanded form

$f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60$

3 0

3 years ago