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finlep [7]
3 years ago
14

IHKGHUSOHUOSLSO ANSWER

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Area of the triangle is 1/2 base x height

1/2(6)x(7)

21m^2

Area of the rectangle is l x b

6 x 10

60m^2

Total area = area of triangle + area of reactangle

Total area = 21m^2 + 60m^2

Therefore total area is 81m^2

WITCHER [35]3 years ago
6 0

I REALIZED I DID IT WRONG SO UH IGNORE WHAT I SAID IM SORRY D:

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2 pounds of zucchini for 4 servings
shepuryov [24]

Answer:

One pound of zucchini equals about 4 cups grated zucchini;

Step-by-step explanation:

2 cups of salted and squeezed zucchini; about 1 cup mashed zucchini; and 3 cups chunked zucchini.

5 0
2 years ago
What do a rectangle and a rhombus have in common? Select all that apply.
sleet_krkn [62]
<span>The opposite sides are parallel.
</span><span>Their angle measures add to 360°.</span>
3 0
3 years ago
At the bright-as-day light bulb factory, 5 out of each 136 bulbs produced are defective. If the daily production is 2720 bulbs,
lions [1.4K]

Answer:

100 lightbulbs

Step-by-step explanation:

Basically find the percentage of lightbulbs that are bad. 5/136. So about 3. 6 percent. I'm going to use a more exact form of this percent for my calculations though. Now use the decimal for of this (0.036....) and multiply it by 2720. Using my exact decimal, the answer just so happened to be exactly 100. So there will be 100 defective lightbulbs per day. (Teachers are a stickler for units, so don't forget them if it's for a teacher)

Hope this helps!

4 0
3 years ago
The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i
kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.


Recall the formula for the sum of consecutive positive integers,

\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2

Now,

1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224

numbers, and their sum is

\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of 1+9\times2=19.

So, the sum of the first 1234 terms in the sequence is 2419.

8 0
2 years ago
Find the following angles<br>​
Serga [27]

Answer:

Downwards ↓

Step-by-step explanation:

a°=90° (right angle)

c°=45° (diagonal)

b°=180-63 (angles on a straight line)

=117°

3 0
3 years ago
Read 2 more answers
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