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finlep [7]
3 years ago
14

IHKGHUSOHUOSLSO ANSWER

Mathematics
2 answers:
kipiarov [429]3 years ago
8 0

Area of the triangle is 1/2 base x height

1/2(6)x(7)

21m^2

Area of the rectangle is l x b

6 x 10

60m^2

Total area = area of triangle + area of reactangle

Total area = 21m^2 + 60m^2

Therefore total area is 81m^2

WITCHER [35]3 years ago
6 0

I REALIZED I DID IT WRONG SO UH IGNORE WHAT I SAID IM SORRY D:

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A rubber ball has a radius of about 2.86 in. Can the ball be packaged in a box shaped like a cube with a volume of 125 in3?
Vlada [557]

Answer:

I am not sure what the values needed to add in / etc, but here is the height of the box: 5

Step-by-step explanation:

A cube is a kind of rectangle where all the sides are the same. So to find volume, cube the length of any side. To find height, calculate the cube root of a cube's volume. For this example, the cube has a volume of 125. The cube root of 125 is 5. The height of the cube is 5.

(hopefully this is correct, have a nice day!)

6 0
3 years ago
Simplify. Express your answer using a single exponent.<br> (2m3)4
Lorico [155]

Answer:

16m^12

Step-by-step explanation

8 0
3 years ago
Identify the values that will make this equation true (x+1)(x+2)=0
liubo4ka [24]

Answer:

-1, -2

Step-by-step explanation:

Since multiplication by 0 will result in 0, any value of x resulting in 0

(-1+1)(-1+2)=0

0x1=0

(-2+1)(-2+2)=0

-1x0=0

3 0
3 years ago
Find the exact solution to the equation. Show your work for credit. (1 point) four to the power of quantity twelve minus four x
padilas [110]
4^(12-4x)=256  realize that 256 is 4^4  so we really have:

4^(12-4x)=4^4  taking the natural log of both sides

(12-4x)ln4=4ln4  dividing both sides by ln4

12-4x=4  subtract 12 from both sides

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x=2


7 0
3 years ago
From a practice assignment:<br>solve the following differential equation given initial conditions ​
hodyreva [135]

If y' = e^y \sin(x) and y(-\pi)=0, separate variables in the differential equation to get

e^{-y} \, dy = \sin(x) \, dx

Integrate both sides:

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Use the initial condition to solve for C :

-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2

Then the particular solution to the initial value problem is

-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2

(A)

4 0
2 years ago
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