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ANEK [815]
3 years ago
7

Divide 270 in the ratio 3:2:1​

Mathematics
1 answer:
Contact [7]3 years ago
6 0

3 + 2 + 1 = 6

270 ÷ 6 = 45

45 × 3 = 135

45 × 2 = 90

45 × 1 = 45

3 : 2 : 1

135 : 90 : 45

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A family has an annual income of ​$30,600 Of​ this, 1/4 is spent for​ food, 1/5 for​ housing, 1/10 for​ clothing, 1/9 for​ savin
Ksenya-84 [330]

Answer:

$6,120

Step-by-step explanation:

1/5 (one-fifth) of the family's annual income ($30,600) is spent on housing- as the word problem states.

You have to find 1/5 (one-fifth) of* $30,600.

Write it out as an equation.

\frac{1}{5}  \times 30600

*The <em>of</em><em> </em>in the word equation (1/5 of 30600) simply means multiplication.

4 0
2 years ago
What is the solution of the equation?
nadya68 [22]

Answer:

q = 4

Fully simplifying this equation gives you answer (A) q = 4

Hope this helps!

8 0
3 years ago
Marcy charges $575 per month to rent a room at her eight-room apartment complex. Running the complex costs
vodka [1.7K]

Answer:

B

Step-by-step explanation:

575 x 8 = 4600

4600 x 12 = 55200

55200 - 9880 = 45320

Therefore, our answer is B

6 0
2 years ago
Read 2 more answers
Choose the correct simplification of the expression (b^5)4
tangare [24]

Answer:

b^20

Step-by-step explanation:

when the exponents have one inside and the other outside, they are multiplied.  

8 0
3 years ago
Media experts claim that daily print newspapers are declining because of Internet access. Listed​ below, from left to right and
yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The test statistic  t_{\alpha/2} is 6.678155

(d) The p value is  1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median  

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean,  \bar{x}_{1}= 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median  

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean,  \bar{x}_{2}}= 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The formula for t test is given by;

t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic  t_{\alpha/2} = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0
3 years ago
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