What is the value of x PLEASE HELP

Consider the following hypothesis test: H 0: 20 H a: < 20 A sample of 60 provided a sample mean of 19.5. The population stand

viva [34]

Answer:

We reject the null hypothesis and accept the alternate hypothesis. Thus, it be concluded that the population mean is less than 20.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 60

Sample mean, $\bar{x}$ = 19.5

Sample size, n = 60

Alpha, α = 0.05

Population standard deviation, σ = 1.8

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 20\\H_A: \mu < 20$

We use One-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{19.5 - 20}{\frac{1.8}{\sqrt{60}} } = -2.151$

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.64$

Since,

$z_{stat} < z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, it be concluded that the population mean is less than 20.

5 0

3 years ago

Hello, PLEASE ANSWER ASAP!!! Don't report my question or give me false answers but I'm freaking out. I was biking home from scho

faltersainse [42]

Answer:

Kuroo Here!

Step-by-step explanation:

Just Tell the truth. Your parents don't want you do die. So Just say the truth. There is nothing good after telling lies.

5 0

2 years ago

Read 2 more answers

Write the expression as one involving only sin x and cos x. sin 2x + cos x

AfilCa [17]

Answer:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

Step-by-step explanation:

Given the expression: sin 2x + cos x,

then we can use the formula: sin 2x = 2 sin x cos x, which gives:

sin 2x + cos x = 2 sin x cos x + cos x = (2 sin x + 1)cos x

So there you have two expressions in terms of sin x and cos x, as requested. :D

6 0

1 year ago

Find the hypotenuse of a right triangle if side a=3 and side b=4

Slav-nsk [51]

Answer:

5 units

Step-by-step explanation:

By Pythagoras theorem:

$(hypotenuse)^2 = a^2+ b^2\\\therefore hypotenuse = \sqrt{a^2+ b^2} \\\therefore hypotenuse = \sqrt{3^2+ 4^2} \\\therefore hypotenuse = \sqrt{9+ 16} \\\therefore hypotenuse = \sqrt{25} \\\therefore hypotenuse = 5\: units$

4 0

3 years ago

Find the area of the figure below A.832in^2 B.768^2 C.416^2 D.384in^2

lesantik [10]

The area is the average of the 2 heights times the base, which is:
(24+16)/2*19.2=384 in^2=D

6 0

2 years ago