(x+3)(x+3) = x^2 -3 + 3x
x^2 + 3x + 3x + 9 = x^2 + 3x - 3
x^2 + 6x + 9 = x^2 + 3x - 3
6x + 9 = 3x - 3
3x + 9 = -3
3x = -12
x = -4
Check:
(-4+3)^2 = (-4)^2 - 3(1+4)
(-1)^2 = 16 - 3(5)
1 = 16-15
1 = 1 :)
Consider two <u>right triangles</u>:
1. ΔABC with <u>vertices</u> A(0,0), B(0,2), C(6,0). Then AB is perpendicular to AC and AB=2 units (<u>vertical leg</u>), AC=6 units (<u>horizontal leg</u>).
2. ΔXYZ with vertices X(6,-10), Y(6,0), Z(36,-10). Then XY is perpendicular to XZ and XY=10 units (vrrtical leg), XZ=30 units (horizontal leg).
The equation of the line BC is
Check whether points Y and Z lie on this line:
Y(6,0): - true;
Z(36,-10): - true.
Answer: the hypotenuses of these two triangles could lie along the same line
Answer:A
Step-by-step explanation:
Step1: group the first two terms together
next step 2:factor out a GFC from each separate binomical
next step 3: factor out the common binomial