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vagabundo [1.1K]
3 years ago
5

What are the coordinates of points P and S?

Mathematics
1 answer:
Elis [28]3 years ago
7 0

9514 1404 393

Answer:

  D. P(-4,4) and S(-3,-2)

Step-by-step explanation:

The first coordinate is the number of units right of the vertical y-axis. Point P is 4 units left, so has an x-coordinate of -4. (Eliminates choices A and B)

The second coordinate is the number of units above the horizontal x-axis. Point P is 4 units up, so has a y-coordinate of +4. (Eliminates choice C)

The coordinates of points P and S are ...

  P(-4,4) and S(-3,-2) . . . . . matches choice D

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460(60%)
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460(.6) 
This now can be represented by the number 276.Since we know that 276 is 60% of 460, The total number of students that have pets will be 276.
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Find each percent decrease. Round to the nearest percent.<br> From 90 points to 45 points
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Answer:

the nearest is 50%

Step-by-step explanation:

45/90 = 0.50 = 50%

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2 years ago
An appliance dealer's website features the mean life expectancy values for major household appliances. A standard refrigerator's
marshall27 [118]

Answer:

There is an 84% probability that your standard refrigerator will last between 12 and 20 years.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A standard refrigerator's mean life expectancy is 18 years with a standard deviation of 2 years. This means that \mu = 18, \sigma = 2.

What is the probability that your standard refrigerator will last between 12 and 20 years?

This probability is the pvalue of Z when X = 20 subtracted by the pvalue of Z when X = 12. So

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 18}{2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{12- 18}{2}

Z = -3

Z = -3 has a pvalue of 0.0014

This means that there is a 0.8413-0.0014 = 0.8399 = 0.84 = 84% probability that your standard refrigerator will last between 12 and 20 years.

5 0
3 years ago
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