Answer:
78
Step-by-step explanation:
do the equation backwards. 157 minus 1 equals 156, and 156 divided by 2 equals <u>78</u>. Hope this helps. pls mark brainliest
A)
![\bf 1990-1910=80\leftarrow t \\\\\\ P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}} \\\\\\ P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}](https://tex.z-dn.net/?f=%5Cbf%201990-1910%3D80%5Cleftarrow%20t%0A%5C%5C%5C%5C%5C%5C%0AP%28t%29%3D8000%282%29%5E%7B-%5Cfrac%7Bt%7D%7B29%7D%7D%5Cimplies%20P%2880%29%3D8000%282%29%5E%7B-%5Cfrac%7B80%7D%7B29%7D%7D%0A%5C%5C%5C%5C%5C%5C%0AP%2880%29%3D8000%5Ccdot%20%5Ccfrac%7B1%7D%7B2%5E%7B%5Cfrac%7B80%7D%7B29%7D%7D%7D%5Cimplies%20P%2880%29%3D%5Ccfrac%7B8000%7D%7B%5Csqrt%5B29%5D%7B2%5E%7B80%7D%7D%7D)
and surely you know how much that is.
b)
since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
The length of the vegetable garden as a function of its length will be given as:
The expression of the garden width in terms of the width of the tomato patch is given as:
- Let the length of the garden be y
- Let the length of the tomato patch be x
If Melissa wants the length of the garden to exceed three times the length of the tomato patch by 2 feet, the length of the vegetable garden as a function of its length will be given as:
If she also wants the garden's width to <u>exceed the width of the tomato patch by 5 feet, t</u>he expression of the garden width in terms of the width of the tomato patch is given as:
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Learn more on functions here: brainly.com/question/19999031
Nitrogen (N) has a molar mass of about 14.007 g/mol, so you have
100.0 g N₂ = (100.0 g) • (1/28.014 mol/g) ≈ 3.570 mol N₂
Hydrogen (H) has a molar mass of about 1.008 g/mol, so
100.0 g H₂ = (100.0 g) • (1/2.016 mol/g) ≈ 49.60 mol H₂
In the balanced reaction, 1 mole of N₂ reacts with 3 moles of H₂ to make 2 moles of NH₃. We have
3.570 • 3 ≈ 10.71
so the reaction would use up all 3.570 mol N₂ and 10.71 mol H₂ to produce about 7.139 mol NH₃.
(A) H₂ is the excess reactant. There is an excess of 49.60 - 10.71 ≈ 38.89 mol H₂.
(B) N₂ is the limiting reactant. All of the N₂ gets consumed in the reaction.
(C) NH₃ has a molar mass of (14.007 + 3 • 1.008) g/mol = 17.031 g/mol. This reaction would theoretically yield about 7.139 mol NH₃, or
7.139 mol NH₃ = (7.139 mol) • (17.031 g/mol) ≈ 121.6 g NH₃
The expression 6000 + 50 + 5 in standard form is 6.055 * 10^3
<h3>How to express in standard form?</h3>
The expression is given as:
6000 + 50 + 5
Evaluate the sum
6055
A number in standard form is represented as
a * 10^b
Where:
0 < a < 1
b is an integer
So, we have:
6055
Multiply by 1
6055 * 1
Express 1 as 1000/1000
6055 * 1000/1000
This gives
6.055 * 1000
Express 1000 as 10^3
6.055 * 10^3
Hence, 6000 + 50 + 5 in standard form is 6.055 * 10^3
Read more about standard form at:
brainly.com/question/1708649
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