Answer:
The mean is 11.5 minutes and the standard deviation is of 6.64 minutes
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The mean is:

The standard deviation is:

Arrival time of 9:18 am and a late arrival time of 9:41 am.
9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.
Mean:

Standard deviation:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes
Answer:
30 < m
The solution would be (30, ∞)
Explanation:
For company A:
The charge is: $96 for any number of mileage ..............> I
For company B:
The charge is $75 fixed and 0.7 for each mileage m. This means that the charge is: 75 + 0.7m .................> II
We want the charge of company A to be less than the charge of company B. This means that we want I to be less than II.
Therefore,
96 < 75 + 0.7m
96 - 75 < 0.7m
21 < 0.7m
21/0.7 < m
30 < m
This means that for any mileage greater than 30, the charge of company A will be less than the charge of company B
Hope this helps :)