Answer:
The zeroes are 2, -2, -6, 5.
Step-by-step explanation:
If 2 of the zeroes are 2 and -2 then (x - 2)(x + 2) is factor of the polynomial.
We can now do long division.
Note (x - 2)(x + 2) = x^2 - 4, so we have:
x^2 - 4 ( x^4 + x^3 - 34x^2 - 4x + 120 ( x^2 + x - 30 <--- Quotient
x^4 - 4x^4
x^3 - 30x^2 - 4x
x^3 -4x
-30x^2 + 120
-30x^2 + 120
x^2 + x - 30 = 0
(x + 6)(x - 5) = 0
x = -6, 5.
We are asked to decide if the expression:
x^2 + y^2 = 1 represents a function.
We recall that in order to have a function, we need for a given value of x to have a SINGLE value of y associated with it.
So in this case, when x is 0 for example, we have the following:
0^2 + y^2 = 1
then y^2 = 1
and we realize that there are TWO values of y whose square form gives 1 (one is 1 and the other -1) Therefore, this relationship is NOT a function, since for example when x = 0 there are TWO values of y to which that x is associated (y = 1 and y = -1).
So please select that this is NOT a function for your answer.
Your question seems incomplete :-(
