X= a number
(2x+4)/3 + (x+2)= 20
Multiply everything by 3 to eliminate the fraction
(3/1)((2x+4)/3) + (3)(x+2)= (3)(20)
2x+4+3x+6= 60
5x+10=60
Subtract 10 from both sides
5x=50
divide both sides by 5
x=10
Check:
Substitute answer in original equation
(2x+4)/3 + (x+2)= 20
(2(10)+4)/3+(10+2)= 20
(20+4)/3+12= 20
24/3+12= 20
8+12= 20
20=20
Hope this helps! :)
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A: adding together 2 and 3 a bunch of times
2+3+2+3+2+3 etc does not equal 28. a possible answer can be 27 students.
Step-by-step explanation:
In order to get the inverse of equation, we will interchange the variables and solve for x and y as follows.

whereas, 
or x = 
Now, on interchanging the variable we will get the equation as follows.


y = 