Answer:
£1,330.46
Hope this helps, mate!
Step-by-step explanation:
Hope this helps, mate! :)
Answer:
All of them are irrational except √9 which is rational.
Step-by-step explanation:
√5= 2.2606797749(irrational)
√9=3(rational) this one is rational
√7=2.64575131106(irrational)
√3.31662479035(irrational)
hope it helps.
Reggie’s speed = distance/time
Reggie’s speed = 40.2 / 2.5
Reggie’s speed = 16.08 mi/hr
Craig’s speed = distance/time
Craig’s speed = 30.8 / 1.875
Craig’s speed = 16.43 mi/hr
Hence, answer is Craig
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
Degree = 1
Step-by-step explanation:
Given:
The differential equation is given as:
The given differential equation is of the order 2 as the derivative is done 2 times as evident from the first term of the differential equation.
The degree of a differential equation is the exponent of the term which is the order of the differential equation. The terms which represents the differential equation must satisfy the following points:
- They must be free from fractional terms.
- Shouldn't have derivatives in any fraction.
- The highest order term shouldn't be exponential, logarithmic or trigonometric function.
The above differential equation doesn't involve any of the above conditions. The exponent to which the first term is raised is 1.
Therefore, the degree of the given differential equation is 1.
