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iren [92.7K]
3 years ago
16

Kevin says that lines p and m will eventually intersect. Lines A and B intersect. Plane A contains lines p, m, and n. Line n is

horizontal on the plane. Lines p and m are both going in the same direction and are identical. Plane B contains vertical line l which forms a right angle with line n. Is Kevin correct?
Mathematics
1 answer:
ANTONII [103]3 years ago
8 0

Answer:

No, because they are parallel.

Step-by-step explanation:

The lines p and m will not intersect, so Kevin is not correct.

It is given that planes A and B intersects. The plane A contains the line p, m and n on its plane. The lines p and m are parallel to each other. They are identical and move in the same direction.

Since the line p and m are parallel, they will not meet each other at any point because parallel lines does not intersect or meet at a point, they run parallelly along each other.

So, line p and m will not intersect.

Thus the answer is " No, because they are parallel."

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storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

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3 years ago
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8 0
3 years ago
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X² + 2x²-3x-6<br><br> Get the zeros
kati45 [8]
Write the polynomial as an equation.
y
=
x
3
−
2
x
2
−
3
x
+
6
y
=
x
3
-
2
x
2
-
3
x
+
6
To find the roots of the equation, replace
y
y
with
0
0
and solve.
0
=
x
3
−
2
x
2
−
3
x
+
6
0
=
x
3
-
2
x
2
-
3
x
+
6
Replace
y
y
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0
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x
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2
,
√
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√
3
x
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2
,
3
,
-
3
The result can be shown in multiple forms.
Exact Form:
x
=
2
,
√
3
,
−
√
3
x
=
2
,
3
,
-
3
Decimal Form:
x
=
2
,
1.73205080
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−
1.73205080
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4 years ago
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Answer:

1/2

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