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Anarel [89]
3 years ago
6

Convert log_8 1=0 into an exponential equation o 1^0=8 O 0^8=1 o '8^0=1 o '8^=8

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Given:

The logarithmic equation is:

\log_81=0

To find:

The exponential equation for the given logarithmic equation.

Solution:

We have,

\log_81=0

It can be rewritten as:

8^{\log_81}=8^{0}

Using a^{\log_ax}=x, we get

1=8^0

8^0=1

Therefore, the correct option is C.

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The temperature of the air in the afternoon was 4°c, and in the evening -2°
charle [14.2K]
4- -2 = 6 degree change
4 0
3 years ago
I also got this one wrong as well can someone tell me what I'm doing wrong so I can change it
Angelina_Jolie [31]
The answer is:  [D]:  "Subtract 5 from 10" .
____________________________________
Explanation:
____________________________________
Use the correct order of operations, according to the mnemonic: 
         "PE MD AS".

The "P" stands for "parentheses", which takes top (first priority); and there are values in parentheses in this expression—specifically, the "(10 - 5)" .  So the first step is to "subtract 5 from 10" —which is:  "Answer choice: [D]".
    Your error was starting at the beginning of the problem; and not using the "order of operations".
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6 0
3 years ago
Please help me<br><br>I will give you 20 points ​
otez555 [7]
Your dividing number for both is by 8. Since 8 hours divided by 8 equals 1. You will do the same to the top and get an answer of 25 miles!!
7 0
2 years ago
4/3+căn5 - 8/1+căn5 +15/căn5
padilas [110]

Answer:

A= \frac{4}{3 +  \sqrt{5} }  -  \frac{8}{1 +  \sqrt{5} }  +  \frac{15}{ \sqrt{5} }

=  \frac{4(3 -  \sqrt{5)} }{4}  -  \frac{8(1 -  \sqrt{5} }{ - 4}  +  \frac{15 \sqrt{5} }{5}  = 3 -  \sqrt{5 + 2 - 2 \sqrt{5 + 3 \sqrt{5 = 5} } }

Step-by-step explanation:

Cảm \:  ơn!!!!

4 0
2 years ago
A, B and C are events such that P(A) = 1/3, P(B) = ¼, and P(C) = 1/5. Find P(AUBUC) under each of the following assumptions: a)
marta [7]

(a) If A,B,C are mutually exclusive, then

P(A\cap B)=P(A\cap C)=P(B\cap C)=P(A\cap B\cap C)=0

so we have

P(A\cup B\cup C)=P(A)+P(B)+P(C)=\dfrac{47}{60}

(b) If A,B,C are mutually independent, then

P(A\cap B)=P(A)P(B),

P(A\cap C)=P(A)P(C),

P(B\cap C)=P(B)P(C),

P(A\cap B\cap C)=P(A)P(B)P(C)

so that

P(A\cup B\cup C)=P(A)+P(B)+P(C)-(P(A\cap B)+P(A\cap B)+P(B\cap C))+P(A\cap B\cap C)

P(A\cup B\cup C)=\dfrac{47}{60}-\left(\dfrac1{12}+\dfrac1{15}+\dfrac1{20}\right)+\dfrac1{60}

P(A\cup B\cup C)=\dfrac35

5 0
3 years ago
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