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2 years ago

6

Convert log_8 1=0 into an exponential equation o 1^0=8 O 0^8=1 o '8^0=1 o '8^=8

1 answer:

Ilia_Sergeevich [38]2 years ago

6 0

Given:

The logarithmic equation is:

$\log_81=0$

To find:

The exponential equation for the given logarithmic equation.

Solution:

We have,

$\log_81=0$

It can be rewritten as:

$8^{\log_81}=8^{0}$

Using $a^{\log_ax}=x$ , we get

$1=8^0$

$8^0=1$

Therefore, the correct option is C.

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8. A box is filled with candies in different colors. We have 40 white candies, 24 green ones, 12

Darya [45]

Answer:

$P(Green\ or\ Red) = 0.30$

Step-by-step explanation:

Given

$White = 40$

$Green = 24$

$Red = 12$

$Yellow = 24$

$Blue = 20$

Required

$P(Green\ or\ Red)$

The total numbe of candy is:

$Total = 40 + 24 + 12 + 24 + 20$

$Total = 120$

This probability is calculated as:

$P(Green\ or\ Red) = P(Green) + P(Red)$

For each, we have:

$P(Green\ or\ Red) = \frac{Green}{Total} + \frac{Red}{Total}$

Take LCM

$P(Green\ or\ Red) = \frac{Green+Red}{Total}$

$P(Green\ or\ Red) = \frac{24+12}{120}$

$P(Green\ or\ Red) = \frac{36}{120}$

$P(Green\ or\ Red) = 0.30$

8 0

3 years ago

I put a ladder 1.5m away from a tree. the ladder is inclined at 70 degrees about the horizontal. What is the height of the tree?

lyudmila [28]

Answer:

4.121216129m

Step-by-step explanation:

use sohcahtoa

tan(70) x 1.5m = 4.121216129m

8 0

3 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

Solve the system of equations.<br> 8.2 + 5y = 24<br> y = -42<br> C =<br> y =

Paul [167]

Answer:

8.2 + 5y = 24 is y = 3.16

y = -42 = 0

c=1

y=1

Step-by-step explanation:

i think these confirm to graphs if i'm wrong just tell me and i'll edit my question.

7 0

3 years ago

ALGEBRA<br> EQUATION<br> PLEASE HELP ASAP<br><br> -3=12y-5(2y-7)

Dovator [93]

Simplify:

−3=12y−5(2y−7)

−3=12y+(−5)(2y)+(−5)(−7)(Distribute)

−3=12y+−10y+35

−3=(12y+−10y)+(35)(Combine Like Terms)

−3=2y+35

Flip the equation.

2y+35=−3

Subtract 35 from both sides.

2y+35−35=−3−35

2y=−38

Divide both sides by 2.

2y/2=−38/2

y=−19

3 0

3 years ago

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