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3 years ago

IM TIMEDDD HELP!! Which shows a rational number plotted correctly on a number line?

Mathematics

2 answers:

topjm [15]3 years ago

7 0

The second one. Is correct

IrinaVladis [17]3 years ago

6 0

I guess the one with 2

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A new house was purchased for $304 000. after 3 years, it's market value had increase by 28%. What is the new market value if th

loris [4]

Answer:

389,120

Step-by-step explanation:

8 0

3 years ago

In a 24 km race, during which each runner maintains a constant speed throughout, Alice crosses the finish line while Becky is st

mr_godi [17]

Answer:6km

Step-by-step explanation:

Given

when Alice finishes the race Becky is 8km From finishing line

and caitlin 12 km from finishing line.

Suppose t is the time require by Alice to finish the race

and $V_a,V_b,V_c$ be the velocity of alice ,becky and caitlin

thus $t=\frac{24}{V_a}=\frac{24-8}{V_b}=\frac{24-12}{V_c}$

thus $\frac{V_b}{V_c}=\frac{4}{3}$

say t' is time required by beckey to complete 8 km thus

$V_b\times t'=8$

therefore for Caitlin

$V_c\times t'=\frac{8}{V_b}\times V_c=6$

Thus caitlin will cover a distance of 6 km in t' time and 6 km away from finishing.

7 0

3 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

7 0

3 years ago

Which one is a linear equation?<br> 2y + 5y^2 - 3 = 0<br> 2y + 5 = 0<br> 2y^5 = 0<br> 2y^2 - 3 = 0

Arlecino [84]

Linear equation should be the last one

6 0

3 years ago

Erika found out that after working in her current job for 9 months she has earned 6 days of vacation

Arte-miy333 [17]

Answer:

4 days

Step-by-step explanation:

9 months/6 months = 6 days /x days

9/6 = 6/x

x = 4

6 0

3 years ago