Answer:
Final cost = £779
Step-by-step explanation:
It is given that:
Cost of summer holiday = £650
Amount increased by 11%
Increased cost = 11% of 650
Increased cost = ![\frac{11}{100}*650](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B100%7D%2A650)
Increased cost = 0.11 * 650 = £71.50
Amount after increment = 650 + 71.50 = £721.50
Further increase = 8%
Amount = 0.08 * 721.50 = £57.72
Final cost = 721.50 + 57.72 = £779.22
Thus,
Final cost = £779
Answer:
Y = 4
Step-by-step explanation:
12 - 8 = 4 and if you put another triangle it will look like a complete square, so you will need to subtract it Hope it Helps
Answer:
The probability is 0.971032
Step-by-step explanation:
The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.
The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:
![P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28x%29%3D%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D%2Ap%5E%7Bx%7D%2A%281-p%29%5E%7Bn-x%7D)
In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:
(eq. 1)
So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:
P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)
We can also calculated that as:
P(x ≥ 5) = 1 - P(x ≤ 4)
Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)
Then, if we calculate every probability using eq. 1, we get:
P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765
P(x ≤ 4) = 0.028968
Finally, P(x ≥ 5) is:
P(x ≥ 5) = 1 - 0.028968
P(x ≥ 5) = 0.971032
The square root of 81 is 9
Answer:
I think it is 1
Step-by-step explanation: