Answer:
1094
Step-by-step explanation:
You have to formulate equations for this problem.
Let S = Science score
M = Math score
C =
Chemistry score
To illustrate the given:
0.9S = 0.75M
0.9S = 0.8C
You are given that Karen’s Math score is 96 marks. You have
to substitute the Math score to the first equation.
0.9S = 0.75(96)
0.9S = 72
S = 80
Therefore, Karen’s Science score is 80. Now, you have to
substitute the Science score to the second equation.
0.9(80) = 0.8C
0.8C = 72
C = 90
So, Karen’s Chemistry score is 90.
Therefore, the total score of the 3 subjects is 266 (96 + 80
+ 90).
Answer:
1
Step-by-step explanation:
To answer this question, we need to that any number (except zero) raised to power 0 is equal to 1. With that in mind, let's solve this:
2y^0 - (3y)^0
= 2(1) - (1)
= <u>1</u>
<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>2</em><em>y</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>y</em><em>^</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em>(</em><em>1</em><em>)</em><em> </em><em>=</em><em> </em><em>2</em><em> </em><em>w</em><em>h</em><em>e</em><em>r</em><em>e</em><em>a</em><em>s</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(</em><em>2</em><em>y</em><em>)</em><em>^</em><em>0</em><em> </em><em>=</em><em> </em><em>1</em>
Rearrange slightly...
12xy-8y-9x+6 now factor 1st and 2nd pair of terms
4y(3x-2)-3(3x-2)
(4y-3)(3x-2)
