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labwork [276]
3 years ago
14

How many real equations does 8-4x=o have ?

Mathematics
1 answer:
Gala2k [10]3 years ago
7 0

Answer:1 real solution

Step-by-step explanation:

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3 years ago
Factor the following and find the zeros.
yaroslaw [1]
1.\ x^2-169=0\\\\x^2-13^2=0\\\\(x-13)(x+13)=0\iff x=13\ \vee\ x=-13

2.\ x^2+14x+49=0\\\\x^2+2x\cdot7+7^2=0\\\\(x+7)^2=0\\\\(x+7)(x+7)=0\iff x=-7

3.\ x^2-17x+42=0\\\\x^2-14x-3x+42=0\\\\x(x-14)-3(x-14)=0\\\\(x-14)(x-3)=0\iff x=14\ \vee\ x=3

4.\ 2x^2-9x-5=0\\\\2x^2-10x+x-5=0\\\\2x(x-5)+1(x-5)=0\\\\(x-5)(2x+1)=0\iffx=5\ \vee\ x=-\frac{1}{2}

5.\ 3x^2+11x-4=0\\\\3x^2+12x-x-4=0\\\\3x(x+4)-1(x+4)=0\\\\(x+4)(3x-1)=0\iff x=-4\ \vee\ x=\frac{1}{3}

6.\ this\ same\ like\ 1.\\\\x^2-196=0\\\\x^2-14^2=0\\\\(x-14)(x+14)=0\iff x=14\ \vee\ x=-14
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3 years ago
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