Answer: 29.916 minutes
Step-by-step explanation:
Given the following :
Mean of distribution = 17.8 minutes
Standard deviation of distribution = 5.2 minutes
Percentage of customers to give free lube and oil change service should not exceed 1% if the customer waits beyond the guaranteed time ;
Length of guarantee :
Since % of customers should not exceed 1%
Then probability of not being chosen = (1 - 0.01) = 0.99
Using the z table to find the Zscore of 0.99,
Zscore of 0.99 = 2.33
This is 2.33 standard deviations above the mean
(2.33 × standard deviation) + mean value
(2.33 × 5.2 minutes) + 17.8 minutes
12.116 + 17.8
= 29.916 minutes
Answer:
just apply the formulas then see dummy
Is there an image i don’t understand what expressions you’re asking for?
<u>f(x) = x + 3</u>
f(2) = 2 + 3
f(2) = 5
f(4) = 4 + 5
f(4) = 9
f(6) = 6 + 5
f(6) = 11
{(2, 5), (4, 9), (6, 11)}
B is 90-42=48° since complementary angles add to 90°
