Answer:
QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)
Step-by-step explanation:
The diagram is not shown, but we assume the points are in the sequence ...
P, Q, R, S, T
Since QR = RS, R is apparently the midpoint of QS, So ...
23. QR = 6/2 = 3
24. RS = QR = 3
25. PQ = QR = 3
26. ST = PT -PQ -QS = 20 -3 -6 = 11
27. RP = PQ +QR = 3 +3 = 6
28. RT = RS +ST = 3 +11 = 14
29. SP = PQ +QS = 3 +6 = 9
30. QT = QS +ST = 6 +11 = 17
Wha....... is that.....::
Answer:
Step-by-step explanation:
All the masses here are based on the main mass of the sand. So we will call sand "x". If there is two times as much cement as sand, then cement is 2x; if there is three times as much stone as sand, then stone is 3x. All of these added together equal a mass of 600 kg:
x + 2x + 3x = 600 so
6x = 600 and
x = 100 kg
There are 100 kg of sand. That means that there is 200 kg of cement and 300 kg of stone
