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3 years ago

Write the product using exponents. (−7) (−7) (−7) (−7) (−7) (−7) (−7) (−7)

Mathematics

2 answers:

zhenek [66]3 years ago

8 0

Answer:

(-7)^8

Step-by-step explanation:

You write as (-7) to the power of n where n is the #of times you write (-7)

scoundrel [369]3 years ago

4 0

Answer:

(-7)^8

Step-by-step explanation:

that is my answer!

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

3 years ago

Use what you know about decimals or fractions to explain why (0.2)•(0.002)=0.0004

strojnjashka [21]

Answer:

So any time you are multiplying something, you are making "groups of"

so 3 groups of 2 = 6, 4 groups of 3 = 12

But with decimals or fractions, because they are a value less than zero, the numbers become increasingly small instead of bigger, like standard multiplication.

So for example, 1 group of 1/2 = 1/2

2 groups of 1/4 = 1/2

and so on

hope this helps!

6 0

3 years ago

A vertical pole is supported by a wire that is 26 feet long. If the wire is attached to the ground 24 feet away from the base of

Andrei [34K]

The answer is in the attachment

8 0

3 years ago

A box contains 3 coins. One coin has 2 heads and the other two are fair. A coin is chosen at random from the box and flipped. If

Blababa [14]

Answer: Our required probability is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

Number of coins = 3

Number of coin has 2 heads = 1

Number of fair coins = 2

Probability of getting one of the coin among 3 = $\dfrac{1}{3}$

So, Probability of getting head from fair coin = $\dfrac{1}{2}$

Probability of getting head from baised coin = 1

Using "Bayes theorem" we will find the probability that it is the two headed coin is given by

$\dfrac{\dfrac{1}{3}\times 1}{\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times \dfrac{1}{2}+\dfrac{1}{3}\times 1}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{1}{6}+\dfrac{1}{6}+\dfrac{1}{3}}\\\\=\dfrac{\dfrac{1}{3}}{\dfrac{2}{3}}\\\\=\dfrac{1}{2}$

Hence, our required probability is $\dfrac{1}{2}$

No, the answer is not $\dfrac{1}{3}$

5 0

3 years ago

Really desperate cant find anyone to help me would really appreciate any help i can get

oksano4ka [1.4K]

Let the model for the change in water vapor be

y = x^3 − 8x^2 + 15x

to find the x intercepts we can factor this expression

x^3 − 8x^2 + 15x = x(x−3)(x−5)

the x intercepts are 0, 3, 5

Hope this helps!

3 0

3 years ago