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gtnhenbr [62]
3 years ago
14

Please help I have 3 more questions

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0

Answer: There is no remander

6

↓↓↓Using Long division ↓↓↓

   0 0 6

1 9 1 1 4

 − 0    

   1 1  

 −   0  

   1 1 4

 − 1 1 4

       0

______________________________________

Hope this helps!

chubhunter [2.5K]3 years ago
3 0

Answer:

6

Step-by-step explanation:

no remainder 6 with the remainder of 0

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If the graph of the function g defined by g(x)=-2x^2-8 is translated vertically upward by 6 units it becomes the graph of a func
Aleks [24]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
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\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, let's see yours   \bf \begin{array}{lclcclll}
g(x)=&-2(&1x^2&+0)&-8\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D 
\end{array}

if it shifts up vertically by 6 units, well, then just add 6 to D
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Answer:

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Step-by-step explanation:

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hence

∫(1 - \frac{1}{2}(cos2x + 1)dx

= ∫(1 - \frac{1}{2}cos2x - \frac{1}{2})dx

= ∫(\frac{1}{2} - \frac{1}{2}cos2x)dx

= \frac{1}{2}x - \frac{1}{4}sin2x + c

where c is the constant of integration



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