Answer:
1) x≠7
2) x≠3 or -7
Step-by-step explanation:
1. The given function is
![f(x) = \frac{1}{x - 7}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B1%7D%7Bx%20-%207%7D%20)
This function is undefined if the denominator is equal to zero .
Therefore the restriction is that:
The denominator is not zero.
![x - 7 \ne0](https://tex.z-dn.net/?f=x%20-%207%20%5Cne0)
![x \ne7](https://tex.z-dn.net/?f=x%20%5Cne7)
2) Assuming the second function is
![f(x) = \frac{(x + 7)(x - 9)}{(x - 3)(x + 7)}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Cfrac%7B%28x%20%2B%207%29%28x%20-%209%29%7D%7B%28x%20-%203%29%28x%20%2B%207%29%7D%20)
This function is not defined when the denominator is zero.
This implies that:
![(x - 3)(x + 7) \ne0](https://tex.z-dn.net/?f=%28x%20-%203%29%28x%20%2B%207%29%20%5Cne0)
The restrictions are:
![x \ne3 \: or \: - 7](https://tex.z-dn.net/?f=x%20%5Cne3%20%5C%3A%20or%20%5C%3A%20%20-%207)
Fourth three thousand eighty hundred million seven hundred zero
Answer:
if i were to factor this would be the solution
2(x^2+2x-1)
You just plug 6 in for x so
5(3)(6)-4
15(6)-4
90-4
86
hope it helps