40 i think because when you divide 400 by 10 it equals 40
Answer:
B. (-4,0) and (-3,0)
Step-by-step explanation:
I used a graphing tool to graph the equation. The parabola intercepts at (-4,0) and (-3,0). Therefore, (-4,0) and (-3,0) are the x-intercepts of the equation.
Option B should be the correct answer.
Answer:

Step-by-step explanation:
There are two shuffled decks each of which contains 12 cards.
we need to collect two cards, 1 card from each shuffled decks.
Taking the 1st suffled decks we need to drawn one. The probability of getting 6 from the 1st shuffled decks is
. In this scenario we need to find the probability of not getting 6 from the 2nd shuffled decks. The probability of not getting 6 is
.
The case can also be vice-versa, that is we can get one 6 from the 2nd shuffled decks.
Hence the total probability is
.
Theoritical probability refers to those outcomes which we suppose to be happen. Experimental probability means the outcomes which can come true if tried.
The given scenario is an example of Experimental probability, as it can also be true if tried.
Answer:
Step-by-step explanation:
This is a system of inequalities problem. We first need to determine the expression for each phone plan.
Plan A charges $15 whether you use any minutes of long distance or not; if you use long distance you're paying $.09 per minute. The expression for that plan is
.09x + 15
Plan B charges $12 whether you use any minutes of long distance or not; if you use long distance you're paying $.15 per minute. The expression for that plan is
.15x + 12
We are asked to determine how many minutes of long distance calls in a month, x, that make plan A the better deal (meaning costs less). If we want plan A to cost less than plan B, the inequality looks like this:
.09x + 15 < .15x + 12 and "solve" for x:
3 < .06x so
50 < x or x > 50
For plan A to be the better plan, you need to talk at least 50 minutes long distance per month. Any number of minutes less than 50 makes plan B the cheaper one.
Answer:
Step-by-step explanation:
P(-2,-1) and Q(4,3)
average of x-coordinates = (-2+4)/2 = 1
average of y-coordinates = (-1+3)/2 = 1
midpoint of PQ: (1,1)
distance between midpoint and Q = √((4-1)²+(3-1)²) = √13
(x-1)² + (y-1)² = 13