The given <span>polynomial is ⇒⇒⇒ </span><span>f(x) = x³ - 3x² + 81x - 243
</span>
by factoring the absolute term (243) to find one of the factors of the the polynomial
∴ 243 = (1 * 243) or (3 * 81) or (9 * 27)
check which of the numbers {1 , 3 , 9 , 27 , 81 , 243} make f(x)<span>= 0
</span>
i have checked 3 and it makes <span>polynomial = 0
</span>
i.e: f(3) = 0 ⇒⇒ (x - 3) is one of the factors of f(x)
By using the reminder theorem ⇒⇒ see the attache figure
∴

And ⇒⇒ (x² + 81) is a sum of two squares which can be factored using the complex numbers as following
x² + 81 = ( x + 9i ) ( x - 9i )
∴ f(x) = <span>
x³ - 3x² + 81x - 243 = (x - 3)(x + 9i)(x - 9i)</span>
Well, the data you gave us is confusing, so i'm just going to say that it is the lowest percentage possible 39.1%, because by the choices given, it shouldn't be lower than that
hope this helps
<span>2(1+4n)+10(n-7)=2n-n
distribute
2+8n+10n-70=2n-n
combine like terms
18n-68=n
move n to other side
17n=68
divide
n=4</span>
Answer:
mRP = 125°
mQS = 125°
mPQR = 235°
mRPQ = 305°
Step-by-step explanation:
Given that
Then:
- measure of arc RP, mRP = mROP = 125°
Given that
- ∠QOS and ∠ROP are vertical angles
Then:
- measure of arc QS, mQS = mROP = 125°
Given that
- ∠QOR and ∠SOP are vertical angles
Then:
Given that
- The addition of all central angles of a circle is 360°
Then:
mQOS + mROP + mQOR + mSOP = 360°
250° + 2mQOR = 360°
mQOR = (360°- 250°)/2
mQOR = mSOP = 55°
And (QOR and SOP are central angles):
- measure of arc QR, mQR = mQOR = 55°
- measure of arc SP, mSP = mSOP = 55°
Finally:
measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°
measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°