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natita [175]
3 years ago
10

What is the LCM of 6, 10, and 15? 50

Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer:

1

Step-by-step explanation:

Thepotemich [5.8K]3 years ago
4 0

Answer:

okay

Step-by-step explanation:

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A piece of wire measuring 20 feet is attached to a telephone pole as a guy wire. The distance along the ground from the bottom o
dem82 [27]

Answer: Height at which the wire is attached to the pole is 12 feet.

Explanation:

Since we have given that

Length of the wire = 20 feet

Let the height at which wire is attached to the pole be h

and distance along the ground from the bottom of the pole to the end of the wire be x+4

Now, it forms  a right angle triangle so, we can apply "Pythagorus theorem".

H^2=B^2+P^2\\\\20^2=x^2+(x+4)^2\\\\400=x^2+x^2+8x+16\\\\400=2x^2+8x+16\\\\400=2(x^2+4x+8)\\\\200=x^2+4x+8\\\\x^2+4x-192=0\\\\x^2+16x-12x-192=0\\\\x(x+16)-12(x+16)=0\\\\(x+16)(x-12)=0\\\\x=-16\ and\ 12

But height cant be negative so, height will be 12 feet.

Hence, height at which the wire is attached to the pole is 12 feet.


8 0
3 years ago
I need help on 5 and 6 geometry
DiKsa [7]
That's 5 and that's 6

4 0
3 years ago
What is the domain and the range of these functions?? quick please!!!!!!!!!!
Sever21 [200]
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. A rational function is a function of the form f(x)=p(x)q(x) , where p(x) and q(x) are polynomials and q(x)≠0 .
6 0
3 years ago
Is 33 a prime number? Explain why or why not
viva [34]

Answer:

No

Step-by-step explanation:

It is not a prime number because it is divisible by 1, 3, 11 and itself, 33.

If it were just 33 and 1, it would be prime, but it has those extra factors

6 0
3 years ago
Please help me please will give brainliest to anyone ​
DaniilM [7]

Answer:

x^4+x^2-12

Step-by-step explanation:

We'll write the polynomial using only the roots required to simplify calculations. However, it states the final answer should not have a radical or complex number in. Therefore, we need to rid them:

(x+\sqrt{3})(x-\sqrt{3})(x-2i)(x+2i)

Expanding this, we get:

(x^2-3)(x^2+4),\\\fbox{$x^4+x^2-12$}.

8 0
3 years ago
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