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Ludmilka [50]
3 years ago
13

What are the four levels of access rights?

Computers and Technology
1 answer:
Svet_ta [14]3 years ago
5 0

Explanation:

Currently, there are four primary types of access control models: mandatory access control (MAC), role-based access control (RBAC), discretionary access control (DAC), and rule-based access control (RBAC). Each model

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I need help now I really do what is the answer thank you
Svetradugi [14.3K]
The answer is c
just replace the y with the y value and the x with the x value
4 0
3 years ago
Using Sequential Search on an array of size n, the search key is definitely present in the array. The probability of matching th
MissTica

Answer:

(11n-5) / 12 is correct answer.

Explanation:

The Probability that key will match to nth term = 1/2

The Probability that key will match to n-1th term = 1/3

As all other probabilities are equal

The Total Probability that key matches to any of 1 to n-2 index = 1 - 1/2 - 1/3 = 1/6

The Probability that key matches to any of 1 to n-2 index = (1/6) / n-2 = (1/6)* (n-2))

Let P(i) = Probability that key matches to ith index.

The Average time complexity = 22 i=1 P(i) * i

The Average time complexity = 1/(6(n-2) * ( sum of 1 to n-2 ) + (n-1) / 3 + n/2

The Average time complexity = 1/(6(n-2) * ( n-2)*(n-1) / 2 + ( n-1) / 3 + n/2

The Average time complexity = 1/6 * (n-1)/2 + (n-1)/3 + n/2

The Average time complexity = (n-1)/12 + (n-1)/3 + n/2

The Average time complexity = (n-1 + 4 * n - 4 * 1 +6 * n)/12

The Average time complexity = 11n-5 / 12

so (11n-5) / 12 is correct answer.

7 0
3 years ago
Write a program that will add up the series of numbers: 99,98, 97...3.2.1. The program should print the running total as well as
Gekata [30.6K]

Answer:

result = 0

for i in range(99, 0, -1):

   result += i

   print(result)

Explanation:

7 0
3 years ago
PLS HELP) Early word processors ran on devices that looked like digital _______?
stealth61 [152]
I looked it up it just says true
8 0
3 years ago
Read 2 more answers
There is a simple method for constructing a magic square for any odd value of n:
DaniilM [7]

Answer:

See Explaination

Explanation:

class MagicSquare():

def __init__(self,side):

self.side=side

self.two_dimension=[]

for row in range(1,side+1):

row_line=[]

for col in range(1,side+1):

row_line.append(0)

self.two_dimension.append(row_line)

def display(self):

row=0

col=int((self.side-1)/2)

for i in range(1,self.side**2+1):

self.two_dimension[row][col]=i

row-=1

col+=1

if row==-1:

row=self.side-1

if col==self.side:

col=0

if self.two_dimension[row][col]==0:

continue

else:

row+=1

if row==self.side:

row==0

for line in self.two_dimension:

for num in line:

print("{0:>3}".format(num),end=" ")

print()

def main():

for i in range(1,14,2):

square=MagicSquare(i)

square.display()

print("----------------------------------------------------")

if __name__ == '__main__':

main()

3 0
3 years ago
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