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3 years ago

Solve for f(-2) PLEASE HELPPPPP

Mathematics

2 answers:

lidiya [134]3 years ago

8 0

F(-2) means the value of x is -2

Replace x with -2 and solve:

3^-2 = 1/9

5 x 1/9 = 5/9

Answer: D.5/9

viva [34]3 years ago

7 0

Answer:

5/9

Step-by-step explanation:

f(x) = 5 * 3^x

Let x = -2

f(-2) = 5 * 3^-2

We know a^-b = 1/a^b

= 5 * 1/3^2

= 5/9

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Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

Kamila [148]

Answer:

Step-by-step explanation:

The fractions are: $\frac{1}{5}$ and $\frac{2}{3}$ . Let's take a look at the denominators: 5 and 3. The LCD of 5 and 3 is 15. 5x3=15, 3x5=15. So now we would multiply the denominators to make them the same number like this: $\frac{5}{15}$ and $\frac{10}{15}$ . Remember that if you multiply the denominator by a certain number, you must multiply the numerator by the same number as well. For example, in $\frac{2}{3}$ , we multiply 3 by 5 and 2 by 5. Same number. Now with that out of the way, let's work on the equation: $\frac{1}{5}$ + $\frac{2}{3}$ . We know it is the same as $\frac{5}{15}$ and $\frac{10}{15}$ . So now all we do is add the numerators together: 5+10=15 or $\frac{15}{15}$ . Now we have to reduce the fraction. $\frac{15}{15}$ can be reduced to 3 by dividing 15 by 5=3. The final fraction is $\frac{3}{3}$ or can be simply put as 3 since 3/3 is a whole number. That's it - you're done!

7 0

2 years ago

1.Encuentra de dos formas diferentes el área de las figuras mostradas en cada literal:

MA_775_DIABLO [31]

Answer:

Cuadrilátero A: $A = y^{2}+4\cdot y +4$

Cuadrilátero B: $A = a^{2}+6\cdot a + 9$

Step-by-step explanation:

Existen dos formas distintas de determinar las áreas de cada cuadrilátero:

(i) Obtener el área de cada cuadrado y sumar los resultados.

(ii) Calcular los lados del cuadrilátero grande y determinar el área.

Cuadrilátero A

Método (i)

$A = y^{2}+2\cdot y +4+2\cdot y$

$A = y^{2}+4\cdot y +4$

Método (ii)

$A = (y+2)\cdot (y+2)$

$A = y^{2}+4\cdot y + 4$

Cuadrilátero B

Método (i)

$A = a^{2}+3\cdot a +9 + 3\cdot a$

$A = a^{2}+6\cdot a +9$

Método (ii)

$A = (a+3)\cdot (a+3)$

$A = a^{2}+6\cdot a + 9$

8 0

2 years ago

On a map, 2.5 inches represents 52 miles. What is the actual distance represented by 5 inches on the map?

nikklg [1K]

Answer:

104 miles

Step-by-step explanation:

52/2.5 = 20.8

20.8 miles = 1 inch

20.8 x 5

104 miles = 5 inches

7 0

3 years ago

Read 2 more answers

5. A function is given below. f(x) = 3x2 - x + 6 What is f(2)? 2

goldenfox [79]

Answer: 10

Step-by-step explanation:

f(x)= 3 (2) - x + 6

f(x)= 6 - 2 + 6

f(x)= 4 + 6

f(x) = 10

7 0

3 years ago

Read 2 more answers

A riverboat travels 54 km downstream in 2 hours. It travels 57 km upstream in 3 hours. Find the speed of the boat and the speed

irakobra [83]

Here we must write and solve a system of equations to find the speed of the boat and the speed of the stream. We will find that the boat's speed is 23km/h and the river's speed is 4km/h.

First, remember the relation:

Distance = Speed*Time.

Now let's define the variables we will be using:

B = boat's speed
R = river's speed.

When the boat travels downstream, the total speed of the boat is the speed of the boat plus the speed of the river, and we know that in that case it travels 54km in 2 hours, then:

54km = (B + R)*2h

When the boat travels upstream, we must subtract the speed of the river. In that case, we know that the boat travels 57km in 3 hours, then we have:

57km = (B - R)*3h

Then our system of equations is:

54km = (B + R)*2h

57km = (B - R)*3h

To solve this, first, we need to isolate one of the variables in one of the equations, let's isolate B in the second one:

57km = (B - R)*3h

57km/3h + R = B

19 km/h + R = B

Now we can replace that in the other equation:

54km = (B + R)*2h

54km/2h = B + R

27 km/h = B + R = (19 km/h + R) + R

Now we can solve this for R:

27 km/h = 19km/h + 2*R

27 km/h - 19km/h = 2*R

8 km/h = 2*R

(8km/h)/2 = 4km/h = R

Now that we know the value of R, we can use:

B = 19 km/h + R = 19 km/h + 4km/h = 23 km/h

So the boat's speed is 23km/h and the river's speed is 4km/h.

If you want to learn more, you can read:

brainly.com/question/12895249

5 0

3 years ago