How would someone Algebraically determine X-Y intercepts?

Mathematics

1 answer:

Savatey [412]3 years ago

7 0

Answer:

y-int: -6

x-int: -2/5 and 3

Step-by-step explanation:

you can find the y-intercept by substituting zero in for every 'x' in the equation;

y = 5(0) - 13(0) - 6

y = -6

to find the x-intercept(s), factor the trinomial by trying to find a pair of factors that multiply to 6 and add to -13; the factors that work are:

(5x + 2)(x - 3)

now set each factor equal to zero and solve for 'x':

5x + 2 = 0

5x = -2

x = -2/5

x - 3 = 0

x = 3

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a pyramid has a regular hexagonal base with side length of 4 and a slant height of 6. what is the total area of the pyramid

Stels [109]

So hmm notice the picture below

the pyramid itself, is really, just one regular hexagon, at the bottom
and 6 triangles, stacked up at each other at the edges

now, if you just get the area of the regular hexagon, and the 6 triangles, add them up, that'd be the total surface area of the pyramid then
$\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}\cdot n\cdot s^2\cdot cot\left( \frac{180}{n} \right)\qquad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of a side}\\
\frac{180}{n}=\textit{angle in degrees}\\
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n=6\\
s=4
\end{cases}\\\\\\ A=\cfrac{1}{4}\cdot 6\cdot 4^2\cdot cot\left( \frac{180}{6} \right)$

now, for the triangles, well, area of a triangle is 1/2 bh, as you'd know, and you have both