The answer is <span>D) Organisms in the population must express no mating preferences.
Some of the conditions that must be met for a </span><span>population or an allele to be in Hardy-Weinberg equilibrium are:
1. The population must be <u>very la</u><u>rge</u> - so A) could not be the right answer.
2. There must be <u>no migration</u> and population must be isolated - so B) could not be the right answer.
3. There must be <u>no mutations</u> - so C) could not be the right answer.
4. There must be <u>random mating</u>, which means there are <u>no mating preferences</u> - so, D) is the right answer.
</span>
There are two main reasons. First, there are introns and exons existed in eukaryotes. Introns do not contain the genetic information but are in large amount in chromosome. So, if the mutation occurs in the introns, it will be recessive. Second, one amino acid will corresponding to several base sequences. For example, UUU and UUC all represent Phe. This is called degeneracy. So if the mutation did not change the amino acid, it is also recessive.
Answer:
It should be D but selective breeding would work because of the selection of dog breeders trying to get new dogs such as a cockapoo which is a cocker spanole and a poodle. Also many other dog breeds that were selected to try out and breed.
Explanation:
I think it is compound, that is a I think so I might be wrong
Asiatic pennywort (Centella asiatica)
Castor (Ricinus communis)
China rose (Hibiscus rosa-sinensis)
Guava (Psidium guajava)
Mango (Mangifera indica)
Papaya ( Carica papaya)
Radish (Raphanus sativus)
Rose (Rosa indica)
Sunflower ( Helianthus annuus)
Tamarind (Tamarindus indicus)
