The second option is the answer
The answer is 0 if I’m wrong correct me but I got 0
Answer:
197
Step-by-step explanation:
So, if you catch 100 fish on both days, that means that you have caught 200 fish. 100 on one day and 100 on the next. But, since you've caught 3 fish twice, that means that three out of 200 fish are the same and cannot be counted as new fish. So 3 from 200 is 197 fish. Hope this helped!
Day 1: 100 (3 tagged)
Day 2: 97 (3 tagged)
100+97=197
or
Day 1: 100 (3 tagged)
Day 2: 100 (3 tagged)
100+100= 200
200-3=197
Answer, 197 fish.
The formulas for conditional probability are:
![P(A\cap B')=P(A)\cdot P(B'|A)](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%27%29%3DP%28A%29%5Ccdot%20P%28B%27%7CA%29)
![P(A\cap B')=P(B')\cdot P(A|B')](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%27%29%3DP%28B%27%29%5Ccdot%20P%28A%7CB%27%29)
.
Since
![P(A\cap B')= \frac{1}{6}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%27%29%3D%20%5Cfrac%7B1%7D%7B6%7D%20)
and
![p(B')= \frac{7}{18}](https://tex.z-dn.net/?f=p%28B%27%29%3D%20%5Cfrac%7B7%7D%7B18%7D%20)
, you have the equation
![\frac{1}{6} = \frac{7}{18} \cdot P(A|B')](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B6%7D%20%3D%20%5Cfrac%7B7%7D%7B18%7D%20%5Ccdot%20P%28A%7CB%27%29)
.
Therefore,
![P(A|B')= \frac{1}{6} : \frac{7}{18} =\frac{1}{6} \cdot \frac{18}{7} = \frac{3}{7}](https://tex.z-dn.net/?f=P%28A%7CB%27%29%3D%20%5Cfrac%7B1%7D%7B6%7D%20%3A%20%5Cfrac%7B7%7D%7B18%7D%20%3D%5Cfrac%7B1%7D%7B6%7D%20%5Ccdot%20%5Cfrac%7B18%7D%7B7%7D%20%3D%20%5Cfrac%7B3%7D%7B7%7D%20)
.
Answer: The correct choice is D.