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Fofino [41]
3 years ago
5

A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random v

ariable X = "number on a chip in the bag."
What is the expected number of a chip that is randomly chosen from the bag?

Mathematics
1 answer:
Dima020 [189]3 years ago
4 0

Answer: 2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

3/11 because you have 3 labeled 2

6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

2 x 3/11 = 0.5454 = 0.55

3 x 6/11 = 1.63

Then add them all together to find the μ

0.18 + 0.55 + 1.63 = 2.36

Hope that helps, plz put a good rating

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The confidence interval can be calculated from the margin of error, and vice versa,

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The confidence interval is given as:

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brainly.com/question/13990500

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