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3 years ago

Which is the simplified form of the expression below? 6w + 23 + 3w A. 3w+23 B. 6w+3w C. 6w+23 D. 9w+23

Mathematics

1 answer:

zalisa [80]3 years ago

7 0

Answer:

D, 9w + 23

Step-by-step explanation:

Add like terms.

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Is the following number rational or irrational? π/2

serious [3.7K]

Answer:

Irrational

Step-by-step explanation:

Because it's π can be represented as 22/7 (not exact value) so it's irrational

3 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLEST!!

anzhelika [568]

Answer:

Step-by-step explanation:

Part A

Eq of line passing through C and A

$y-y_o=m(x-x_o)\\y-6=\frac{6-1}{1-2}(x-1)~=>y=-5x+11\\\\PERPEDICULAR~ LINE\\\\m_2=-\frac{1}{m_1}=-\frac{1}{-5}=\frac{1}{5}\\y-3=\frac{1}{5}(x-3)~=>y=\frac{1}{5}x+\frac{12}{5}$

Part B

Coordinates of point D

$-5x+11=\frac{1}{5}x+\frac{12}{5}=>11-\frac{12}{5}=x(\frac{1}{5}+5)=>x=\frac{43}{26}\\y=-5(\frac{43}{26})+11=\frac{71}{26}\\D(\frac{43}{26}, \frac{71}{26})$

Part C

Distance DB

$h=\sqrt{(\frac{43}{26}-3)^2+(\frac{71}{26}-3)^2}=\frac{7}{\sqrt{26}}$

Part D

Length of base

$base=\sqrt{(2-1)^2+(1-6)^2}=\sqrt{26}$

$area=\frac{1}{2}base*h=\frac{1}{2}\sqrt{26}*\frac{7}{\sqrt{26}}=\frac{7}{2}$

8 0

3 years ago

How to find the area and perimeter of irregular rectangles

LenaWriter [7]

To find the perimeter of irregular shapes in general, you just add the length of the sides.
To find the area of irregular shapes, first, draw a line to separate the two shapes, then find the area of those two shapes and add them up.

4 0

3 years ago

which number could be multiplied by each side of the equation to produce the equivalent equation x=12?

zmey [24]

I want to say 6 not shuer cause i suck at math hope this helped tho

6 0

3 years ago

Two forces of 401 newtons and 477 newtons act on a point. The resultant force is 828 newtons. Find the

Ray Of Light [21]

Answer:

The answer is " $39.01^{\circ}$ "

Step-by-step explanation:

$\to R= 828\\\\\to F_1= 401\\\\\to F_2=477\\\\\to \bold{R=\sqrt{F_1^2+F_2^2+2F_1F_2 \cos \theta}}$

$828=\sqrt{401^2+477^2+2 \times 401 \times 477 \cos \theta}\\\\828=\sqrt{160801+227529+382554 \cos \theta}\\\\828=\sqrt{388330+382554 \cos \theta}\\\\$

square the above equation:

$(828)^2=(\sqrt{388330+382554 \cos \theta})^2\\\\$

$685584 =388330+382554 \cos \theta\\\\685584 -388330=382554 \cos \theta\\\\297254=382554 \cos \theta\\\\\cos \theta=\frac{297254}{382554}\\\\\cos \theta=0.777025\\\\\theta= \cos^{-1} 0.777025\\\\\theta= 39.01^{\circ}$

3 0

3 years ago