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2 years ago

Please help me with my algebra homework?

Mathematics

1 answer:

USPshnik [31]2 years ago

4 0

Answer:

Step-by-step explanation:

a=1

r=-6/1=-6

$S_{7}=a\frac{1-r^n}{1-r} =1\frac{1-(-6)^7}{1-(-6)} \\=\frac{1+6^7}{1+6} \\=\frac{1+279936}{7} \\=\frac{279937}{7} \\=39991$

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A random sample of 7 fields of durum wheat has a mean yield of 29.8 bushels per acre and standard deviation of 3.62 bushels per

meriva

Answer:

CI = 29.8 ± 3.53

Critical value is z = 2.58

Step-by-step explanation:

First of all let's find margin of error. It is given by the formula;

ME = zσ/√n

We are given;

Standard deviation; σ = 3.62

Sample size; n = 7

Mean; x¯ = 29.8

Now, z-value for 99% Confidence level is 2.58

Thus;

ME = (2.58 × 3.62)/√7

ME = 3.53

CI is written as;

CI = x¯ ± ME

CI = 29.8 ± 3.53

Critical value is z = 2.58

5 0

2 years ago

Kelly used 3 2/9 packs of notebook paper in the first 1/6 of the year. At what rate is Kelly using notebook paper.

Makovka662 [10]

Answer:

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4 0

2 years ago

Pls solve fast ! I’m begging you ! The lesson is operations on functions

Oliga [24]

Step-by-step explanation:

1a. Just add both of them.

$8x - 3 + 4x + 5 = 12x + 2$

1b. We just subtract both of the functions.

$(8x - 3) - (4x + 5) =$

$4x - 8$

1c.

$(8x - 3)(4x + 5)$

$32 {x}^{2} + 28x - 15$

1d.

$\frac{8x - 3}{4x + 5} = 2 - \frac{13}{4x + 5}$

3 0

2 years ago

So I need to put them in the order can you please help me

Alex787 [66]

Answer:

2.112

Step-by-step explanation:

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4 0

3 years ago

When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of

makkiz [27]

Answer:

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So $A(t) \alpha \sin (\frac{t - \alpha }{k} )$

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

$A(t) = 2.2\sin \frac{(t)}{k} + 0.6$

at t = 2 sec volume of a is 0.6

So function reduce to

$A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6$

and t = 5 max value of volume is represent

so,

$\sin \frac{t - \alpha }{k} = 1$

$\frac{t - 2}{k} = \frac{\pi }{2}$ when t = 5

$\frac{6}{\pi } = k$

so the equation becomes

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

7 0

2 years ago