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2 years ago

Please help me with my algebra homework?

Mathematics

1 answer:

USPshnik [31]2 years ago

4 0

Answer:

Step-by-step explanation:

a=1

r=-6/1=-6

$S_{7}=a\frac{1-r^n}{1-r} =1\frac{1-(-6)^7}{1-(-6)} \\=\frac{1+6^7}{1+6} \\=\frac{1+279936}{7} \\=\frac{279937}{7} \\=39991$

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What's the answer to this problem.

frutty [35]

The answer is B. by SAS

8 0

3 years ago

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Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?

Lubov Fominskaja [6]

Answer:

yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

For the first parabola, the point of intersection is ...

y^2 = 4(-y-1)

y^2 +4y +4 = 0

(y+2)^2 = 0

y = -2 . . . . . . . . one solution only

x = -(-2)-1 = 1

The point of intersection is (1, -2).

For the second parabola, the equation is the same, but with x and y interchanged:

x^2 = 4(-x-1)

(x +2)^2 = 0

x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

_____

Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0

3 years ago

Find the mode of 7 , 3 , 2 , 5 , 0. Single choice. 2 0 No mode

frez [133]

Answer:

No mode

Step-by-step explanation:

The mode is the statistical method in which the most repetitive number should be considered

Like if we take an example

1,1, 2, 2, 2, 4, 4,4,4

So here the mode is 4 as 4 is repeated 4 times

But in the given situation there is no mode as every number is written single time

5 0

2 years ago

Elizabeth has $10, $5, and $1 bills worth $101. she has five more five dollar bills than ten dollar bills and 4 times more 1 dol

vesna_86 [32]

Let x be number of $10 dollar bills

Let y be number of $5 dollar bills

Let z be number of $1 dollar bills

From the question, we can come up with three equations (so we can find the values of x, y & z) :

10x + 5y + z = 101
y - x = 5
z = 4x

The first equation comes from finding the total money Elizabeth has, which is $101.

The second equation comes from value of y (number of $5 bills) is more than value of x (number of $10 bills) by 5 dollars.

The third equation comes from the value of z (number of $1 bills) being 4 times more than the value of x (number of $10 bills).

Now, we will begin to find the value of x, y & z.

From the first equation,

10x + 5y + z = 101

Substitute the third equation (z = 4x) into z:

10x + 5y + 4x = 101

Simplify this and you get,

14x + 5y = 101

Now, we use the second equation. The second equation is y - x = 5. If we try to make y as the subject, it becomes y = 5 + x.

Now, substitute this into the value of y of the last working we did:

14x + 5(5+x) = 101

Simplify that and it becomes:

x = 4

Then, substitute this value of x into the second and third equations to find y and z.

y - x = 5

y - 4 = 5

y = 9

z = 4x

z = 4(4)

z = 16

Finally, let's check these answers by substituting them into the first equation to try and see if the total value is really $101.

10x + 5y + z = 10(4) + 5(9) + 16

10x + 5y + z = 40 + 45 + 16

10x + 5y + z = 101

Thus, our answers are correct. Elizabeth has FOUR $10 bills, NINE $5 bills and SIXTEEN $1 bills.

6 0

2 years ago

Read 2 more answers

Find lim h→0 f(2+h)-f(2)/h if f(x)=x^2+x+1

bekas [8.4K]

Answer:

Step-by-step explanation:

$\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

$\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}$

$\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}$

$\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}$

$\displaystyle\lim_{h \to 0} h + 5$

= 5

8 0

2 years ago