Personality. Hope this helped!
Search is the information processing approach describes problem-solving as a process involving.
<h3>What is
information processing?</h3>
Information is acquired, recorded, arranged, retrieved, distributed, displayed, and processed. Recent usage of the phrase has been particularly prevalent when referring to computer-based processes.
Identification of the stimulus, selection of the response, and programming of the response are the three separate stages of information processing.
Through selective attention and information processing, performers are better able to recognize pertinent cues, which increases movement reactions and, eventually, results in good performance.
Thus, it is a search.
For more details about information processing, click here:
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The automobile engine is the largest source of **<span>carbon monoxide**</span> gas.
Answer:
Total Surface Area of Solid = C.s.a of hemisphere+C.s.a of cone+C.s.a of Cylinder
slant height of cone=√h²+r²
=√6²+8²
=√100
=10cm
height of cone = 10 cm
radius of hemisphere =radius of cone=radius of cylinder=8cm
T.S.A of solid=2πrh+2πr²+πrl
=πr[2h+2r+l]
=3.14*8[2*10+2*8+10]
=25.12[36+10]
=25.12*46
=1155.52 cm²
Explanation:
hope this helps
Answer:

Explanation:
Your question has one part only: <em>a) The average weight of the eggs produced by the young hens is 50.1 grams, and only 25% of their eggs exceed the desired minimum weight. If a Normal model is appropriate, what would the standard deviation of the egg weights be?</em>
<em />
<h2><em>Solution</em></h2><h2><em /></h2>
You are given the <em>mean</em>, the reference value, and the <em>percent of egss that exceeds that minimum</em>.
In terms of the parameters of a normal distribution that is:
- <em>mean</em> =<em> 50.1g</em> (μ)
- Area of the graph above X = 51 g = <em>25%</em>
Using a standard<em> normal distribution</em> table, you can find the Z-score for which the area under the curve is greater than 25%, i.e. 0.25
The tables with two decimals for the Z-score show probability 0.2514 for Z-score of 0.67 and probabilidad 0.2483 for Z-score = 0.68.
Thus, you must interpolate. Since, (0.2514 + 0.2483)/2 ≈ 0.25, your Z-score is in the middle.
That is, Z-score = (0.67 + 0.68)/2 = 0.675.
Now use the formula for Z-score and solve for the <em>standard deviation</em> (σ):


