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xz_007 [3.2K]
3 years ago
6

For the set (1,1,2,4,5,6,7,8,10) would each of the following measures be affected if another value of 10 was included?

Mathematics
1 answer:
NeTakaya3 years ago
6 0

Answer:

Step-by-step explanation:

range-no

mean-yes

median-yes

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On a coordinate plane, a line goes through (negative 4, 0) and (0, 2).
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A C D

Step-by-step explanation:

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If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres
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\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
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8 0
3 years ago
Mike and Teegan each measured the volume of the 16-ounce bottle three times. They recorded their measurements as shown. Mike: 16
-BARSIC- [3]

Answer:

The correct option is;

Mike's measurement are more precise and more accurate

Step-by-step explanation:

The given information are;

The mass of the measured bottle = 16-ounce

The record of the measurements made by Mike are;

16.4 oz

15.2 oz

15.8 oz

The record of the measurements made by Teegan are;

16.34 oz

16.59 oz

15.13 oz

From the two measurements, we have;

The precision of a measurement depends on how close the values of the measurement are to one another, therefore, we have;

For Mike, the precision is given as follows

16.4 - 15.2 = 1.2

16.4 - 15.8 = 0.6

15.8 - 15.2 = 0.6

Total difference = 1.2 + 0.6 + 0.6 = 2.4

For Teegan , the precision is given as follows

16.59 - 16.34 = 0.25

16.59 - 15.13 = 1.46

16.34 - 15.13 = 1.21

Total difference = 0.25 + 1.46 + 1.21 = 2.92

Therefore, Mike's measurements are more precise than Teegan's measurements

The accuracy of the measurement is the amount of closeness the measurements are to a given value

In the question, the given value is 16-ounces of the volume of the bottle

Therefore, by the mean absolute deviation from the 16-ounce of the bottle, we have;

For Mike;

Mean \ absolute  \ deviation = \dfrac{\left | 16.4 - 16 \right | + \left | 15.2 - 16 \right | + \left | 15.8 - 16 \right | }{3} = 0.533

For Teegan, we have;

Mean \ absolute  \ deviation = \dfrac{\left | 16.34 - 16 \right | + \left | 16.59 - 16 \right | + \left | 15.13 - 16 \right | }{3} = 0.6

Therefore, Mike's measurement is more accurate than Teegan's measurement.

Which gives;

Mike's measurement are more precise and more accurate.

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