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Masja [62]
3 years ago
5

A buoy moves up and down with the waves in simple harmonic motion. This buoy moves a total of 12 feet from its minimum position

to its maximum position. The buoy returns to its maximum point every 10 seconds. Find the following.
a. Amplitude
b. Period
c. Frequency
d. An equation for the buoys position
e. If the buoy has a bell that makes a sound whenever it is 2 from its maximum height. State the time intervals between bell rings. You may answer as a decimal accurate to the hundredths place. Note that there are two answers (a short interval and a longer interval).
Mathematics
1 answer:
Lana71 [14]3 years ago
3 0
That was rude of him
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Blababa [14]

Answer: 1.18 OR 0.18

Step-by-step explanation:

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3 years ago
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How do i solve this inequality? Number 46
myrzilka [38]
6(x-2.5) ≥ 8-6(3.5+x)

A number is before a parenthesis. The first step is to multiply.

6(x-2.5) = 6x -15

8-6(3.5+x)
2(3.5+x)= 7+2x

6x-15≥7+2x

Now solve

6x-15≥7+2x
-2x -2x

(-2x+2x)= They cancel out

(6x-2x)= 4x

4x-15≥7
+15 +15

4x≥22
/4 /4

You get= x≥5.5
7 0
3 years ago
Two angles are complementary. The measure of one angle is 6º more than five times the measure of the other angle. Find the
Salsk061 [2.6K]

Complementary means that the two angles sum to 90 degrees.

So based on the problem, let:

1st angle=5x+6

2nd angle=x

Now create an equation.

x+5x+6=90

6x=84

x=14

5x+6=76

answer: 14 degrees and 76 degrees

6 0
3 years ago
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Please I need some help on this
ivann1987 [24]

It wouldbe D.) because you would do

12-4=x

x would be the number of adults

you would solve for x and get 8 so you would have to solve so it would be D.)

3 0
3 years ago
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Find an equation of the plane through the point (−5,−1,2) with normal vector ????=⟨−1,−5,2⟩.
Ganezh [65]

Answer:

x + 5y - 2z + 14 = 0

Step-by-step explanation:

A plane that passes through the point (x_{0}, y_{0}, z_{0}) with a normal vector of (a,b,c) has the following equation, initially:

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

After we solve this, we have

ax + by + cz + d = 0

In this problem, we have that:

(x_{0}, y_{0}, z_{0}) = (-5,-1,2)

(a,b,c) = (−1,−5,2)

So

a(x - x_{0}) + b(y - y_{0}) + c(z - z_{0}) = 0

-1(x - (-5)) - 5(y - (-1)) + 2(z - 2) = 0

-(x + 5) - 5(y + 1) + 2(z - 2) = 0

-x - 5 - 5y - 5 + 2z - 4 = 0

-x - 5y + 2z - 14 = 0

Multplying everything by -1

x + 5y - 2z + 14 = 0

3 0
3 years ago
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