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uranmaximum [27]
3 years ago
9

PLEASE HELP ME EASYYYYYY MATH QUESTION BRAINLIEST

Mathematics
1 answer:
Burka [1]3 years ago
7 0

Answer:

8% is equivalent to the fraction 8/100

Step-by-step explanation:

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Find the midpoint between (4,-1) and (3,2)
zepelin [54]

Midpoint has form of,

M(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})

We can insert the data,

M(\dfrac{4+3}{2},\dfrac{-1+2}{2})

Which simplifies to,

\boxed{M(3.5, 0.5)}

Hope this helps.

r3t40

4 0
3 years ago
Emily thinks the perfect tomato sauce has 8 cloves of garlic in every 500{ mL} of sauce. Raphael's tomato sauce has 12 cloves of
igomit [66]

For perfect solution we need to have :-  8 colves   in 500ml    solution

500   ml     has   8 cloves

1 ml             has     8 / 500 cloves

100ml         has   8 / 500  * 100  =    8/5  = 1.6 cloves

Raphael's mixture  

    900 ml  has 12 cloves

      1 ml     has   12 / 900 cloves

   100 ml has   12 / 900 *  100   =    12 / 9  =   1.33 cloves

so concentration of garlic in 100 ml solution of Raphael's solution is less than Emily's solution    so it is not garlicky enough.     ( option B)

5 0
3 years ago
Read 2 more answers
Expand the expression <br><br><br> -7(k - 3)
Illusion [34]
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4 0
3 years ago
A farmer wants to fence a rectangular area of 72 square feet next to a river. Find the length and width of the rectangle which u
Arlecino [84]

Answer:

  • 12 ft parallel to the river
  • 6 ft perpendicular to the river

Step-by-step explanation:

The least fence is used when half the total fence is parallel to the river. That is, the shape of the rectangle is twice as long as it is wide.

72 = W(2W)

36 = W²

6 = W . . . . . . the width perpendicular to the river

12 = 2W . . . .  the length parallel to the river

_____

<em>Development of this relation</em>

Let T represent the total length of the fence for some area A. Then if x is the length along the river, the width is y=(T-x)/2, and the area is ...

  A = xy = x(T -x)/2

Note that the equation for area is that of a parabola with zeros at x=0 and at x=T. That is, for some fence length T, the area will be a maximum at the vertex of this parabola. That vertex is located halfway between the zeros, at ...

 x = (0 +T)/2 = T/2

The corresponding area width (y) is ...

  y = (T -T/2)/2 = T/4

Equivalently, the fence length T will be a minimum for some area A when x=T/2 and y=T/4. This is the result we used above.

8 0
3 years ago
Which graph corresponds with the equation <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%20%7D%20%28x%2B1%29%5E
JulijaS [17]

\qquad\qquad\huge\underline{{\sf Answer}}

The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.

And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.

From the above information, we can easily conclude that the Correct representation is done in graph 4

5 0
2 years ago
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