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lapo4ka [179]
3 years ago
9

How much interest would Mia pay if the simple interest rate were 5%

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

Mia would have a 55$ interest  :)

Step-by-step explanation:

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You are playing a game of Scrabble and have the 5 A tiles, 3 E tiles, 1 Z tile, 2 M tiles, 3 L tiles, and 1 Y tile to choose fro
kaheart [24]
So, what we need to do is find out the chance you will pull an M or an L out of the scrabble bag on your next turn.

Our first step is finding out how many pieces total are in the bag. This will become the denominator in our answer. To do this, we just need to add up all the pieces we know are in the bag! From the question, we know there are <span>5 As, 3 Es, 1 Z, 2 Ms, 3 Ls, and 1 <span>Y left in the bag. So 5 + 3 + 1 + 2 + 3 +1 should give us 15 total pieces to pick from.

Next, we need to know the total of Ls and Ms left in the bag that we want to pick. This number will be the numerator in our answer. From the question, we know there are 2 Ms and 3 Ls in the bag. Because 2+3 = 5, that means out final fraction for this problem should be 5/15!

Unfortunately, that is not an actual answer for the question, so that means we have to simplify by finding the biggest number that goes into both the top and bottom of our fraction. To get 5, we can only use the numbers 1 and 5. To get 15, we can use 1, 3, 5, and 15. From this, it looks like both the top and the bottom are divisible by 5. When we divide the top by 5 we end up with a 1, and when we divide the bottom by 5 we end up with a 3, meaning our final fraction is D) 1/3!</span></span>
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3 years ago
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Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
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Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

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The answer to this question is $15.00
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Answer:

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