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3 years ago

I think of a number, multiply it by three, and add four. I get twenty two.

Mathematics

2 answers:

dlinn [17]3 years ago

6 0

Answer:

the answer should be like 3×6+4=22

Step-by-step explanation:

im not sure with A I mean, forming an equation, I guess it should be 3x+4=22 that's all as texted and for B

what I did was subtract 4 from 22 which I got 18 and then I divided 18 with 3, since the question said it was multiplied by 3.

22-4=18.

18÷3=6. 6×3=18

3×6+4=22

I hope this will help.

melomori [17]3 years ago

3 0

Step-by-step explanation:

3x+4=22

3x=22-4

3x=18

x=18/3

x=6

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3 years ago

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A basket contains four apples and five peaches. Three times, you randomly select piece of fruit, returning to the basket, and th

Anarel [89]

Answer:

100/729

Step-by-step explanation:

The basket contains 9 fruits: 4 apples and 5 peaches. Thus the probability of choosing one fruit can easily be determined.

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If the replacement is allowed, then the probabilities will remain unchanged for all the fruits. Therefore, the probability of selecting an apple in the any attempt is 4/9 and the probability of selecting a peach in any attempt is 5/9. Assuming that the selection of the fruits is independent, we can safely multiply the probabilities. Therefore, 4/9 * 5/9 * 5/9 = 100/729.

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4 years ago

At age 9 the average weight (21.3 kg) and the average height (124.5 cm) for both boys and girls are exactly the same. a random s

Lesechka [4]

Complete Question:

Heights of 9-Year-Olds At age 9 the average weight (21.3 kg) and the average height (124.5 cm) for both boys and girls are exactly the same. A random sample of 9-year-olds yielded these results. Estimate the mean difference in height between boys and girls with 95% confidence. Does your interval support the given claim?

Boys Girls

Sample Size 60 50

Mean Height, cm 123.5 126.2

Population variance 98 120

a.State the hypotheses and identify the claim.

b.Find the critical value(s).

c.Compute the test value.

d.Make the decision.

e.Summarize the results.

Step-by-step explanation:

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Answer:

Answer is contained in explanation.

Step-by-step explanation:

Description of visual:

I started with the first picture. This is a picture of triangle ABC.

Now I'm going to draw a line segment from vertex C such that it is a perpendicular bisector of AB.

Proof:

CM is a perpendicular bisectors of AB is a given.

From this we can concluded by definition of perpendicular angles that angle AMC and angle BMC are right angles.

Since angles AMC and BMC are right angles, then they are congruent to each other.

By the definition of bisector and since CM bisects AB, then AM is congruent to MB.

By the reflexive property, we have that CM is congruent to CM.

We can conclude the two triangles, triangle CMA and CMB, are congruent by SAS Postulate.

Since triangles CMA and CMB are congruent, we can conclude that their corresponding parts are congruent.

Since their corresponding parts are congruent, then we now know that side CA and side CB are congruent.

Since two sides of the triangle ABC are congruent to each other, namely side CA and side CB, then the triangle ABC is an isosceles triangle.

Setup for coordinate geometry proof:

M is the midpoint of AB since CM is a bisector of AB.

Since M is the midpoint of AB, then M is located at the coordinates $(\frac{0+b}{2},\frac{0+0}{2})=(\frac{b}{2},0)$ .

We found this point such that the length AM is equal to the length MB.

That is, the distance between A and M is the same as the distance between M and B.

Let's check.

$AM=\sqrt{(\frac{b}{2}-0)^2+(0-0)^2}$

$AM=\sqrt{(\frac{b}{2})^2+0}$

$AM=\sqrt{\frac{b^2}{4}}$

$AM=\frac{\sqrt{b^2}}{\sqrt{4}}$

$AM=\frac{b}{2}$

$MB=\sqrt{(b-\frac{b}{2})^2+(0-0)^2}$

$MB=\sqrt{(\frac{b}{2})^2+0}$

$MB=\sqrt{\frac{b^2}{4}}$

$MB=\frac{\sqrt{b^2}}{\sqrt{4}}$

$MB=\frac{b}{2}$

We have confirmed that AM=MB.

(Based on the picture, we could have taken a slightly easier route to calculate the distance between M and A, then the distance between B and M. They are both a horizontal distance. So $MB=b-\frac{b}{2}=\frac{b}{2}$ where as $AM=\frac{b}{2}-0=\frac{b}{2}$ .)

Now we also want to assume that the line segment CM is perpendicular to AB. I have drawn the base of the triangle on the x-axis so a vertical line would be perpendicular to it. Also this would make point $C=(c,d)=(\frac{b}{2},d)$ . The $y$ -coordinate is $d$ because we don't know how high above the $x$ -axis the point $C$ is.