Answer:
<h2>x + 2y = 8</h2>
Step-by-step explanation:
The standard form of an equation of a line:
We have:
Convert:
<em>multiply both sides by 2</em>
<em>add x to both sides</em>
Answer:
y = 12
Step-by-step explanation:
set up equation for 'y varies inversely with x': y = k/x
where 'k' is the constant of variation
8 = k/6
therefore, k = 48
value of y when x = 4: y = 48/4; therefore, y = 12
2d+3
2(8)+3
Multiply 2 and 8
16+3
19
So the answer is 19
Answer:
The average score is 85
Step-by-step explanation:
Good Luck!
Answer:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
Step-by-step explanation:
Solve for u:
(x sin(A) - u cos(A))^2 + (x cos(A) + y sin(A))^2 = x^2 + y^2
Subtract (x cos(A) + y sin(A))^2 from both sides:
(x sin(A) - u cos(A))^2 = x^2 + y^2 - (x cos(A) + y sin(A))^2
Take the square root of both sides:
x sin(A) - u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
-u cos(A) = sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) - x sin(A) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or x sin(A) - u cos(A) = -sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Subtract x sin(A) from both sides:
u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or -u cos(A) = -x sin(A) - sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2)
Divide both sides by -cos(A):
Answer: u = x tan(A) - sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) or u = sec(A) sqrt(x^2 + y^2 - (x cos(A) + y sin(A))^2) + x tan(A)
