I'm running low on points can you please help me :) I will give brainiest promise

Mathematics

2 answers:

Citrus2011 [14]3 years ago

4 0

Answer:

dis look like it from flvs lol um imma try nd help out alright

uhhh um itz a bit hard so imma take a guess imma go with b

Step-by-step explanation:

nd since ur running low on points u can go to my account answer my questions with 2+2+4+5=13 or somethin like dat or take a guess

ioda3 years ago

3 0

Answer: the ordered pair negative 3 over 8, negative 5 over 8

Step-by-step explanation:

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Identify the transformation of the function f(x)=|x| by observing the equation of the function g(x)=|x+3|

Alla [95]

Answer:

a horizontal translation by 3 units left

Step-by-step explanation:

f(x)= |x|

we are given with absolute function f(x)

g(x) = |x+3|

To get g(x) from f(x) , 3 is added with x

If any number is added with x then the graph of the function move to the left

Here 3 is added with x, so the graph of f(x) moves 3 units left to get g(x)

So there will be a horizontal translation by 3 units

6 0

2 years ago

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$