Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.
- 1.74/0.25 = 6.96
- The most quarters that can fit into $1.74 is 6.
---Multiply $0.25 by 6 = $1.50
---Subtract $1.50 from $1.74 = $0.24
---We need to use the rest of the coins to fill up $0.24.
Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.
- 0.24/0.10 = 2.4
- The most dimes that can fit into $0.24 is 2.
---Multiply $0.10 by 2 = $0.20
---Subtract $0.20 from $0.24 = $0.04
No nickels can fit into $0.04, because they are worth $0.05.
We can use our least amount (pennies) to fill in the $0.04 remaining.
Your answer is 6 quarters, 2 dimes, and 4 pennies.
Answer:
o I = 4 cm, w = 9 cm, h = 3 cm
Step-by-step explanation:
The volume is given by V = l*w*h
w = 6 cm, I = 4,cm, h = 4 cm V= 6*4*4 = 96
o w = 7 cm, h = 3 cm, I = 5 cm V = 7*3*5 =105
o I = 4 cm, w = 9 cm, h = 3 cm V = 4*9*3 =108
o h = 5 cm, w = 6 cm, I = 3 cm V = 5*6*3 =90
The largest volume is
o I = 4 cm, w = 9 cm, h = 3 cm V = 4*9*3 =108
Answer:
The value is 
The correct option is a
Step-by-step explanation:
From the question we are told that
The margin of error is E = 0.05
From the question we are told the confidence level is 95% , hence the level of significance is
=> 
Generally from the normal distribution table the critical value of is
Generally since the sample proportion is not given we will assume it to be
Generally the sample size is mathematically represented as
![n = [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%20%7D%7B2%7D%20%7D%7D%7BE%7D%20%5D%5E2%20%2A%20%5C%5E%20p%20%281%20-%20%5C%5E%20p%20%29%20)
=> ![n = [\frac{ 1.96 }{0.05} ]^2 *0.5 (1 - 0.5)](https://tex.z-dn.net/?f=n%20%3D%20%5B%5Cfrac%7B%201.96%20%7D%7B0.05%7D%20%5D%5E2%20%2A0.5%20%281%20-%200.5%29%20)
=>
Generally the margin of error is mathematically represented as
Generally if the level of confidence increases, the critical value of 
increase and from the equation for margin of error we see the the critical value varies directly with the margin of error , hence the margin of error will increase also
So If the confidence level is increased, then the sample size would need to increase because a higher level of confidence increases the margin of error.
P = 390,00 + 4000x
450,000 people - (15years x 4000) = 390k in 2010
15 years is the difference between 2010 and 2025
subtract 60k (that is the 15 years multiplied by 4k) from 450k and you get 390k.
Sorry if my explanations suck, I'm not great at explaining my thought process
(3x+4) (2x-6)
6x-18x+4x-24
6x^{2} -14-24
