The probability that both are nervous around strangers is (1/5)(1/5)=1/25
The probability that at least one is nervous around strangers is 1 - 1/25 = 24/25.
Answer:
we have standard deviation of 12 so 298-322 would be 34.1% times 2 which is 68.2%. We also have 12 more in a lower region and we can use normal distribution to find that it would be 13.6% + 68.2%
Answer is 81.8%
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Answer:
B. {-21.-7. 7. 21)
Step-by-step explanation:
The set made up of odd numbers and multiples of 7 is given as;
{-21.-7. 7. 21)
Multiples of 7 are usually those numbers where 7 is factor.
Odd numbers are numbers that cannot be divide by 2.
So, the most fitting answer is B.
Answer:
-1333/1000
Step-by-step explanation:
Evaluate tan(sin^-1(-4/5)).
First we need to evaluate the expression in parenthesis
sin^-1(-4/5)
= sin^-1(-0.8)
= -53.13
SUbstitute the given value into the original expression as shown;
tan(sin^-1(-4/5))
= tan(-53.13)
= -1.333
= -1333/1000
Hence the required answer is -1333/1000
