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anzhelika [568]
3 years ago
10

Help me, solve for x

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Answer:

x=10

Step-by-step explanation:

The two line segments should be equal, so you can set 2x-10 equal to x.

2x-10=x

-10=-x

x=10

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Find the average rate of change of f ( x ) = 9 x 2 − 7 on the interval [ 2 , a ] . Your answer will be an expression involving a
aleksandrvk [35]

Answer:

9a + 18

Step-by-step explanation:

so the first step is to evaluate the value of f(2).

f(2) = 9(2)^2-7\\f(2)=9(4)-7\\f(2)=36-7\\f(2)=29

Now that we have this value we can use the slope formula (y2 - y1) / (x2 - x1) where y2 is f(a), y1 is 29, x2 is a, and x1 is 2

\frac{f(a)-29}{a-2}\\\\\frac{(9a^2-7)-29}{a-2}\\\frac{9a^2-36}{a-2}

Now from here we can use long division to simplify it further

9a^2/a = 9a\\9a(a-2)=9a^2-18a\\(9a^2-36)-(9a^2-18a)\\18a-36\\\\18a/a=18\\18(a-2)=18a-36\\(18a-36)-(18a-36)\\0\\\\9a+18

8 0
2 years ago
What are the roots of the quadratic equation x2+2x=-5
stiks02 [169]

Answer:

x = -1 +/-2i

Step-by-step explanation:

Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.

x² + 2x + 5 = 0

Use the quadratic formula by substituting a= 1, b = 2 and c = 5.

x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i

5 0
4 years ago
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