Question

5x+3y=25 and 3x+4y=26 solve by substitution!

Answer 1

$5x + 3y = 25 \\ 5x = 25 - 3y \\ x = \frac{25 - 3y}{5} \\ x = \frac{25}{5} - \frac{3y}{5} \\ x = 5 - \frac{3y}{5} \\ 3x + 4y = 26 \\ 3 (5 - \frac{3y}{5} ) + 4y = 26 \\ 15 + \frac{11y}{5} = 26 \\ \frac{11y}{5} = 26 - 15 \\ \frac{11y}{5} = 11 \\ \frac{5}{11} \times \frac{11y}{5} = 11 \times \frac{5}{11} \\ y = 5 \\ x = 5 - \frac{3y}{5} \\ x = 5 - \frac{3(5)}{5} \\ x = 2$

(x,y)—> (2,5)