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horsena [70]
3 years ago
11

Several years​ ago, a government agency reported the default rate​ (the proportion of borrowers who default on their​ loans) on

a certain type of loan at 0.035. Set up the null and alternative hypotheses to determine if the default rate this year is less than 0.035.
What are the correct null and alternative hypotheses to test the claim that the default rate is less this​ year?
Mathematics
1 answer:
Tomtit [17]3 years ago
6 0

do you have a picture

Step-by-step explanation:

of the problem

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Of the 37 teachers at Francesca's high school, 9 are female. What is the ratio of the number of male teachers to the total numbe
kvv77 [185]

Answer:

28 : 37

Step-by-step explanation:

Find how many male teachers there are by subtracting 9 from 37:

37 - 9

= 28

Create a ratio with this to the total number of teachers:

28 : 37

So, the ratio of the number of male teachers to the total number of teachers is  28 : 37.

5 0
3 years ago
A manufacturer finds that the revenue generated by selling x units of a certain commodity is given by the function R(x) = 60x −
bonufazy [111]
R(x) = 60x - 0.2x^2

The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150

Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
7 0
3 years ago
Read 2 more answers
In a call center that stays open all the time, calls arrive as a poisson process with a mean rate of 0.3 complaints per hour.(a)
DENIUS [597]

The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.

Data;

  • Mean rate = 0.3
  • x = 50
  • standard deviation = ?

<h3>Poission Rule</h3>

Using poission formula,

P(x=x) = \frac{e^-^\lambda - \lambda^x}{x!}\\\lambda = 0.3 per minute

Let's substitute the values into the formula.

For 50 calls in 150 hours

For 150 hours = x = 0.3 * 150 = 45

p(x=50) = \frac{e^-^4^5 * 45^5^0}{50!} = 0.0431

b)

The probability the next call arrives after 2 hours.

\lambda = 0.3 * 2 = 0.6\\p(x=0) = \frac{e^-^0^.^6 * 0.6^0}{0!} = 0.5488

c)

The number of calls recieved each day is recorded for 50 consecutive days.

for 50 days;

\lambda = 0.3 * 50 * 24 = 360

The mean = 360

The standard deviation is given as

S.D = \sigma =\sqrt{360} = 18.974\\

The probability the sum of these 50 number is less than 356 is

p = (x < 356) = z = \frac{356 - 360}{18.974} = -0.2108\\p(z < -0.2108) = 0.4165

Learn more on poission formula here;

brainly.com/question/7879375

3 0
2 years ago
I'm honestly thee most confused person on earth right now ;-; please help me by EXPLAINING what I'm supposed to be doing
trasher [3.6K]

Answer:

What grade is this for.

Step-by-step explanation:

5 0
3 years ago
Here are some fractions.
Harrizon [31]
A. 10/15
b. 7/8
those r the answers
3 0
3 years ago
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