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Jlenok [28]
3 years ago
8

H E L P SHES UNTO ME

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

33.5

Step-by-step explanation:

To solve, you will use the formula 4/3 of pi times radius cubed.

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-23<br> Simplify your answer as much as possible.<br> =<br> X<br> ?
Murljashka [212]

Answer:

Question is not fully addressed

Step-by-step explanation:

Please put the full question otherwise, i cannot answer it

3 0
3 years ago
0.5+2x &lt; 14.5 whats the answer
aliina [53]

Answer:

x < 7

Step-by-step explanation:

0.5 + 2x < 14.5

2x < 14.5 - 0.5

2x < 14

x < 14 ÷ 2

x < 7

( To solve this is basically solving an equation. It's just that that instead of an equal sign, a greater than, less than, greater than or equal to or a less than or equal to sign is present. )

6 0
3 years ago
12. dress: $70<br> discount: 30%<br> tax: 7%
anyanavicka [17]

Answer:

All you have to do is multiply 45 by 0.70. You will get 31.5, then you subtract 31.5 and 45 to get the answer: $13.50

Step-by-step explanation:

5 0
4 years ago
Can someone fill in the boxes please!
Hunter-Best [27]

Answer:

-28 for the  first box and for the second box it is -4

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
irakobra [83]

Answer:

We need a sample size of at least 383.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 85% confidence level with an error of at most 0.03

We need a sample size of at least n.

n is found with M = 0.03, \pi = 0.21

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.44\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.44\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.44\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^{2} = (\frac{1.44\sqrt{0.21*0.79}}{0.03})^{2}

n = 382.23

Rounding up

We need a sample size of at least 383.

6 0
3 years ago
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