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lora16 [44]
3 years ago
11

The domain for all variables in the expressions below is the set of real numbers. Determine whether each statement is true or fa

lse.(i)∀x ∃y(x+y≥0)
Mathematics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

gdgvb

zgyrrustdtioyrsitetroeso6rsdjxuuF resist yeah hai yasss

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Answer:

No I don't. Sorry!!!!

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Find x and y intercepts of<br> 3x - 2x = 5
uysha [10]

Answer:

x=5

Step-by-step explanation:

there is no y intercept

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3 years ago
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I need a lot of help with practice problems, I am not understanding math right now. Please help!!!!!! Will give brainliest!!
34kurt

Answer:

1. 18 (sqrt21 - sqrt2a)

2. 3

3. x^m/n

4. (5x^4√10)/(√2x)

5. x = -2 or -6

6. x = 30

Step-by-step explanation:

Number 1

3^3sqrt21 - 6^3sqrt2a

3 * 6 * sqrt21 - sqrt2a

18 (sqrt21 - sqrt2a)

Number 2

3^1/2 * 3^1/2 =

3^1/2+1/2 =

3^1 =

3

Number 3

^nsqrtx^m =

x^m/n

Number 4

(√250x^16)/(√2x) =

(√25 * 10 * x^16)/√(2x )=

(5x^4√10)/(√2x)

Number 5

√2x + 13 - 5 = x

√2x + 13 = x + 5

square both side to take away the sqrt sign

(√2x + 13)^2 = (x + 5)^2

expand the equation on the RHS

2x + 13 = x(x+5) + 5(x+5)

2x+13 = x^2 + 10x +25

substract 13 from both sides

2x = x^s + 10x +12

subtract 2x from both sides

0 = x^2 +8x + 12

Factorize equation

x^2 + 6x +2x + 12 = 0

x(x+6) + 2(x+6) = 0

(x+2)(x+6) = 0

x = -2 or -6

Number 6

3 ^5sqrt(x+2)^3 + 3 = 27

subtract 3 from both sides

3 ^5sqrt(x+2)^3  = 27 - 3

3 ^5sqrt(x+2)^3  = 24

divide through by 3

^5sqrt(x+2)^3  = 8

square both sides by 5 to take away the 5th root sign

(x+2)^3  = (8)^5

(x+2)^3  = 32,768

take the cube root of both sides to take away the ^3

x+2 = ^3sqrt 32,768

x+2 = 32

x = 32 - 2

x = 30

3 0
4 years ago
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Are you on I X L?

Step-by-step explanation:

I apoligize but try googling 5% of 50

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