The answer is A since: 3^2+4^2=5^2
25=25
Answer:
The volume of the tetrahedron is:

Step-by-step explanation:
The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.
The equation of the plane formed by the three points is:
Points: (2,0,0);(0,5,0);(0,0,4)

It can also be expressed as:

We have to calculate the triple integral, therefore we must define the domain:
The values of x are given by:
0≤x≤2
We will integrate the values of y between the y = 0 axis and the line formed when z = 0:
z=0 ⇒ 10x + 4y=2 ⇒ 

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20
10x + 4y+5z=20 ⇒ 

The volume of the tetrahedron is:





5) since (x-a)^2+(y-b)^2=r^2
plug in (-5,2) as (a,b) and r=3
Making the equation:
(x+5)^2+(y-2)^2=9
6) (x-0)^2+(y-0)^2=r^2
since we have (0,5)
0^2+5^2=r^2
Final equation: x^2+y^2=25
You can start by subtracting different equations from each other.
3x + 2y + 3z = 1
subtract
3x + 2y + z = 7
2z = -6
divide by 2
z = -3
add the following two expressions together:
3x + 2y + z = 7
3x + 2y + 3z =1
6x + 4y + 4z = 8
subtract the following two expressions:
6x + 4y + 4z = 8
5x + 5y + 4z = 3
x - y = 5
^multiply the whole equation above by 3
3x - 3y = 15
subtract the following two expressions:
3x - 3y = 15
3x + 2y = 10
-5y = 5
divide each side by -5
y=-1
take the following expression from earlier:
x - y = 5
substitute y value into above equation
x - - 1 = 5
2 negatives make a positive
x + 1 = 5
subtract 1 from each side
x = 4
Therefore x = 4, y = -1, z = -3
I checked these with all 3 equations and they worked :)
(it's quite complicated, comment if you don't understand anything) :)
Divide across and see if its proportional meaning that is the same... The answer is 2 so its proportional Hope this helped Im not good at Math but i do understand this i learned it a few days ago Im not a professional though lol I just know how to do this stuff and percents a percent over 100 and X over the number if you ever need help there just like Fractions message me i know how to do proportional relationships Ill try..