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Mandarinka [93]
3 years ago
12

5. Consider the following graph. у 10 9 M 8 7 6 5 4 3 0 1 2. 3 4 5 6 7 8 9 10 -10-9-8-7 -6 -4 -3 -2 -1 -1 T 2 -3 -5 7 K -9 -10 I

f P and Q are the midpoints of MT and JK respectively, then sketch PQ in the above coordinate plane.​
Mathematics
1 answer:
iragen [17]3 years ago
3 0
I need a picture of the graph so I know how to solve!
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Which operation should you perform first in the expression 15 + 7 × (5 − 3) × 42 ÷ 6?
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7 0
3 years ago
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Evaluate 5 minus t divide by 3 when t = 12
DIA [1.3K]
The answer is to your question is 1. You must replace t with 12 and then follow the rule of PEMDAS to solve this equation. 
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3 years ago
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Mika has a mean score of 21 on his first four Spanish quizzes.If each quiz is worth 25 points, what is the highest possible mean
Natalka [10]

Answer:

125 its basically 25 x 5=125

Step-by-step explanation:

3 0
3 years ago
Solve the polynomial equation
ExtremeBDS [4]
Hey there!

You can solve this by squaring both sides to first cancel out the square root on the left. Then, you can eliminate each term as your normally would. 

2 \sqrt{x} =x-3

(2 \sqrt{x})^{2}  = (x-3)^{2}

(4x) = (x-3)(x-3)

4x =  x^{2} -6x+9

x^{2} -10x+9

Now, you're given the opportunity to find your solution using the quadratic formula. That formula is:

\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}

You can find out a, b, and c by comparing your new equation to the standard form. Luckily, we just put our equation into standard form:

ax^{2} + bx + c

x^{2} -10x+9

a = 1 \\ b = -10  \\ c = 9

To find your solution, plug these numbers into the quadratic formula and solve. 

\frac{-b_-^+ \sqrt{b^2-4ac} }{2a}

\frac{10_-^+ \sqrt{-10^2-4(9)}}{2}

Remember to use PEMDAS when solving these problems. 

\frac{10_-^+ \sqrt{100-36}}{2}

\frac{10_-^+ \sqrt{64}}{2}

\frac{10_-^+ 8}{2}

Now, solve this final bit by adding the top terms then subtracting them for two different answers. 

\frac{10 + 8}{2} = 9

\frac{10- 8}{2} = 1

Don't assume that both of these are correct. The very last step is to plug both of these into the original problem you were given and see if they make the equation true. 

2 \sqrt{9} =9-3
2*3=6
6=6

2 \sqrt{1} =1-3
2*1=-2
2 \neq -2

So (finally), your answer will be x = 9. 

Hope this helped you out! :-)
7 0
3 years ago
A rectangle has a perimeter of 44 inches and an area of 72 square inches. What are the lengths of the sides of the rectangle?
kondor19780726 [428]
  • A rectangle has a perimeter of 44 inches and an area of 72 square inches.
  • Perimeter = 44 inches, area = 72 square inches.
  • Let the length and breadth be l and b respectively.
  • We know, perimeter of a rectangle = 2(l + b)
  • Therefore,
  • 2(l + b) = 44

or, l + b = 22

or, b = 22 - l ...(i)

  • We know, area of a rectangle = lb
  • Therefore,
  • lb = 72
  • Putting (i) in b, we get
  • l(22 - l) = 72

or, 22l - l^2 -72 = 0

or, l^2 - 22l + 72 = 0

or, l^2 - 4l - 18l + 72 = 0

or, l(l - 4) - 18(l - 4) = 0

or, (l - 4)(l - 18) = 0

or, l = 4 or l = 18

  • Therefore, if the length is 4 inches, then the breadth is (22-4) inches, i.e., 18 inches.
  • And if the length is 18 inches, then the breadth is (22-18) inches, i.e., 4 inches.

<u>Answer:</u>

<u>B)</u><u> </u><em><u>4</u></em><em><u> </u></em><em><u>inches </u></em><em><u>and </u></em><em><u>1</u></em><em><u>8</u></em><em><u> </u></em><em><u>inches.</u></em>

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0
3 years ago
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